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____ [38]
2 years ago
7

Which two ratios represent quantities that are proportional?

Mathematics
1 answer:
9966 [12]2 years ago
3 0

Answer:

A is correct (33/18 and 66/26)

Step-by-step explanation:

Both fractions equal 6/5 when fully simplified. All you have to do is divide 18 by 15 and divide 24 by 20. Both of them will equal 1.2.

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3x-(-3)=-6 what is the answer to it
stira [4]

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7 0
3 years ago
HURRRYYYYY PLEASEEEEE
zepelin [54]

Answer:

I believe it's 12.

Step-by-step explanation:

The interquartile is the box I think.

7 0
3 years ago
Below are tabulated a number of Rockwell G hardness values that were measured on a single steel specimen. Compute
Mashcka [7]

Answer:

a) 48.408

b) 1.235

Step-by-step explanation:

a)

The average hardness value xbar can be computed as

xbar=sum of values/number of values

xbar=(46.5+46.9+49.4+50.3+49.8+48.8+47+47.7+48.3+49.4+47.8+49)/12

xbar=580.9/12

xbar=48.408 (rounded to 3 decimal places).

The average hardness value is 48.408.

b)

The standard deviation hardness value s can be computed as

s=\sqrt{\frac{sum(x-xbar)^2}{n-1} }

x              x-xbar  (x-xbar) ²

46.5  -1.90833 3.64174

46.9  -1.50833 2.27507

49.4    0.99167 0.98340

50.3     1.89167 3.57840

49.8     1.39167 1.93674

48.8    0.39167 0.15340

47.0           -1.40833 1.98340

47.7   -0.70833 0.50174

48.3           -0.10833 0.01174

49.4    0.99167  0.98340

47.8           -0.60833 0.37007

49.0    0.59167 0.35007

Total                               16.7692

s=\sqrt{\frac{16.7692}{12-1} }

s=\sqrt{\frac{16.7692}{11} }

s=\sqrt{1.5245}

s=1.2347

s=1.235 (rounded to 3 decimal places)

The standard deviation hardness value is 1.235.

4 0
3 years ago
Is the number 1.13 greater than, less than or equal to 1
Fantom [35]
1.13 is greater than 1
3 0
2 years ago
This is correct? I need help please :(
Leto [7]

Answer:

well, we only no that

2l + 2w is 80

(lengths and widths on all 4 sides

and that w * l is A

so the function should be w times what's left for l, but also expressed by something with w

2l + 2w = 80 | -2w

2l = 80 -2w | devide by 2

l = 80 - w

now we can substitute l in

A = w * l

so that we only need w's

A(w) = w * (80-w)

for any w it will give us the area, makes only sense for 0<w<80

8 0
2 years ago
Read 2 more answers
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