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meriva
3 years ago
7

7w + 6(3w + 9) Help ASAP

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
6 0

Answer: 25w+54

Step-by-step explanation:

Distribute:

=7w+(6)(3w)+(6)(9)

=7w+18w+54

Combine Like Terms:

=7w+18w+54

=(7w+18w)+(54)

=25w+54

Answer:

=25w+54

inessss [21]3 years ago
3 0

Answer:

25w + 54

Step-by-step explanation:

7w + 6(3w + 9)

7w + 18w + 54

25w + 54

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Which of the following pairs are corresponding angles?
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4 0
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Read 2 more answers
Ray is constructing a flowerbed for the zoo and wants to
faust18 [17]

Answer:

Option (3)

Step-by-step explanation:

Since, flowerbed is in the shape of a right triangle,

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(Hypotenuse)² = (12)² + (12)²

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4 0
3 years ago
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
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