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Alina [70]
3 years ago
8

Read the power and then check all that apply. 34 = 3 × 3 × 3 × 3 A power is a shorter way to write repeated multiplication. The

base is 3. The base is 4. The exponent is 3. The exponent is 4. The exponent tells you to multiply the 3 together 4 times. The exponent tells you to multiply the 4 together 3 times.
Mathematics
1 answer:
lianna [129]3 years ago
4 0

Answer:

the right one's are  

1,2,5,6

Step-by-step explanation : I hope this helps everyone

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A state is considering license plates that have two digits followed by four letters. Assuming no combinations are excluded, how
love history [14]

Answer:

32,292,000

Step-by-step explanation:

In your question, it asks how many license plate combinations we could make WITHOUT repeats.

We need some prior knowledge to answer this question.

We know that:

  • There are 26 letters in the alphabet
  • We can make 10 digits (0 - 9)

With the information we know above, we can solve the question.

Since we CAN'T have repeats, we would be excluding a letter or number for each license plate.

We're going to need to multiply each "section" in order to find how many combinations of license plates we can make.

We decrease by one letter and one number in each section since we can't have repeats.

Now, we can solve.

Work:

26*25*24*23*10*9 = 32,292,000

When you're done multiplying, you should get 32,292,000.

This means that there could be 32,292,000 different combinations of license plates.

<h3>I hope this helps you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
8 0
3 years ago
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Will give brainliest answer!
kifflom [539]
5x + 60y = 35

x +y = 1.5 : rewrite as x = 1.5-y   and substitute this formula for x in the first one:

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combine like terms:

7.5 + 55y = 35

subtract 7.5 from both sides:

55y = 27.5

divide both sides by 55 to solve for  y

y = 27.5 / 55 = 0.5

now substiute 0.5 for y in the 2nd equation:

x + 0.5 = 1.5

x = 1.5 - 0.5 = 1

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3 years ago
Solve the system. <br> y= -2x + 1<br><br> y= 2x - 3
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Equation 1: y = -2x + 1

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-2x + 1 = 2x - 3

1 = 4x - 3

4 = 4x

x = 1

Then, we need to plug our value of x back into either of the original two equations and solve for y. I will be plugging x back into equation 2 above.

y = 2x - 3

y = 2(1) - 3

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