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Vika [28.1K]
4 years ago
12

4x – 3y=8 2. 5x – 2y = -11

Mathematics
1 answer:
AlladinOne [14]4 years ago
6 0

Answer:

x = -7

y =  - 12

Step-by-step explanation:

The given system is:

4x-3y=8

5x-2y=-11

We make x the subject in the top equation to get:

x =  \frac{3}{4}y + 2

Plug this expression for x in the bottom equation to get

5( \frac{3}{4}y + 2) - 2y=  - 11

We expand to obtain

\frac{15}{4} y + 10 - 2y =  - 11

Multiply through by 4

15y + 40 - 8y =  - 44

Group similar terms

15y - 8y =  - 44 - 40

7y =  - 84

y =  -  \frac{84}{7}  =-12

This means

x =  -12\times  \frac{3}{4}  + 2

x =  - 7

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Answer:

Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f.

Step-by-step explanation:

7 0
3 years ago
What is the domain of the function y= square root x - 5 - 1
IrinaK [193]

Answer:

x\geq 5

Step-by-step explanation:

The function that we have to study in this problem is

y=\sqrt{x-5}-1

The domain of a function is defined as the set of all the possible values of x that the function can take.

For a square-root function, there are some limitations to the possible value of the argument in the root.

In particular, the argument of a square root must be equal or greater than zero, because the square root of a negative number is not defined.

Therefore, in this case, we have to set the following condition for the domain:

x-5\geq 0

And by solving, we get

x\geq 5

which means that the domain of this function is all real numbers equal or greater than 5.

5 0
3 years ago
How many 4 digit numbers consisting of only the digits 2,4,6 and 8 are divisible by 4
Blababa [14]

Answer:

  • digits used once: 12
  • repeated digits: 128

Step-by-step explanation:

In order for a number to be divisible by 4, its last two digits must be divisible by 4. This will be the case if either of these conditions holds:

  • the ones digit is an even multiple of 2, and the tens digit is even
  • the ones digit is an odd multiple of 2, and the tens digit is odd.

We must count the ways these conditions can be met with the given digits.

__

Since we only have even numbers to work with, the ones digit must be an even multiple of 2: 4 or 8. (The tens digit cannot be odd.) The digits 4 and 8 comprise half of the available digits, so half of all possible numbers made from these digits will be divisible by 4.

<h3>digits used once</h3>

If the numbers must use each digit exactly once, there will be 4! = 24 of them. 24/2 = 12 of these 4-digit numbers will be divisible by 4.

<h3>repeated digits</h3>

Each of the four digits can have any of four values, so there will be 4^4 = 256 possible 4-digit numbers. Of these, 256/2 = 128 will be divisible by 4.

7 0
2 years ago
Read 2 more answers
Factor the common factor out of the expression 8+20a+18a^2
ruslelena [56]
First let's rewrite it...

18a^2 + 20a + 8

Factor out a 2

2 (9a^2 + 10a + 4)
5 0
3 years ago
Solve for V.<br> 3y=39<br> Simplify your answer as much as possible.
Crank

Answer:

3y=39 :3

y=13

Step-by-step explanation:

prove me wrong

3 0
3 years ago
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