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4 years ago

Rewrite this expression using appropriate conventions. (a+a+a+a) / 5

Mathematics

1 answer:

NemiM [27]4 years ago

6 0

Answer:

4a/5

Step-by-step explanation:

$(a+a+a+a) / 5 \\ = \frac{4a}{5}$

Solving further ;

Simplify

$4a \div 5 =\frac{4}{5} a$

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The value of the 3 in the number 731.8

Dominik [7]

Answer:

Step-by-step explanation:

the 7 is in the one hundreths place and the 3 is in the tenths place so therefore it is 30. hope this helps :))

5 0

3 years ago

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Given square ABCD, with point P on side AB , point Q on side BC, point R on side CD, and point S on side DA as shown. Additional

sveta [45]

The ratio of the area of square PQRS to the area of square ABCD is 5/9

<h3>Area of square ABCD</h3>

Assume the measure of the side lengths of the square ABCD is 1, then the area of the square ABCD is:

$A_1 = 1 \times 1$

$A_1 = 1$

See attachment for the diagram that represents the relationship between both squares.

<h3 /><h3>Pythagoras theorem</h3>

The measure of length PQ is then calculated using the following Pythagoras theorem:

$PQ^2 = (\frac 13)^2 + (\frac 23)^2$

Evaluate the squares

$PQ^2 =\frac 19 + \frac 49$

Add the fractions

$PQ^2 =\frac 59$

<h3>Area of square PQRS</h3>

The above represents the area of the square PQRS.

i.e.

$A_2 =\frac 59$

So, the ratio of the area of PQRS to ABCD is:

$Ratio = \frac{A_2}{A_1}$

This gives

$Ratio = \frac{5/9}{1}$

$Ratio = \frac{5}{9}$

Hence, the ratio of the area of square PQRS to the area of square ABCD is 5/9

Read more about areas at:

brainly.com/question/813881

8 0

2 years ago

(6x+10)= cos (2x+40)

nevsk [136]

4 is tha answemdmkxkx

3 0

3 years ago

Juanita and Stephanie went to a clearance sale at a clothing store. Juanita bought 4 blouses and 3 skirts for a total of $ 72 .

Inessa05 [86]

4b+3s=72
6b+3s=96
Multiply the second equation by -1
-6b-3s=-96
Now you can cross out the +3s -3s
-2b=-24
Divide both sides by -2
b=12
s=8
So blouses cost $12 each and skirts cost $8 each

4 0

3 years ago

A cat is running away from a dog at a speed of 3m/s. originally, the distance between them was 48 meters. What should be the spe

balandron [24]

Answer:

$3.8\:\mathrm{m/s}$

Step-by-step explanation:

Use the formula $d=rt$ (distance is equal to rate/speed multiplied by time) to solve this problem.

We know that one minute is equal to 60 seconds. Therefore, the distance travelled by the cat in 1 minute is equal to $d=3\cdot 60=180\text{ meters}$ .

To catch the cat, the dog needs to also cover an additional 48 meters, because the cat was initially 48 meters away from the dog and it ran away from the dog. Hence, the dog will need to cover $180+48=228$ meters in one minute.

Therefore, we have:

$228=60r,\\r=\frac{228}{60}=\boxed{3.8\:\mathrm{m/s}}$

5 0

3 years ago

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