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3 years ago

Can someone please help ? ❤️

Mathematics

1 answer:

faust18 [17]3 years ago

5 0

Answer:

Step-by-step explanation:

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2y + 4x = 16<br><br> Anyone know how to solve for Y?

Ede4ka [16]

Answer:

y = -2x + 8

Step-by-step explanation:

In this question, you have to solve for "y".

Solve:

2y + 4x = 16

Get "y" by itself by subtracting 4x from both sides.

2y = -4x + 16

Simplify by dividing both sides by 2.

y = -2x + 8

3 0

3 years ago

Read 2 more answers

−5 i kinda need answers, srry it's so short (don't take this the wrong way)

alukav5142 [94]

Step-by-step explanation:

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3 years ago

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2b^2+4b–2=0 what is the answer?

s2008m [1.1K]

$2b^2+4b-2=0\\
2(b^2+2b-1)=0\\
2(b^2+2b+1-2)=0\\
2((b+1)^2-2)=0\\
2(b+1)^2-4=0\\\
2(b+1)^2=4\\\
(b+1)^2=2\\
b+1=-\sqrt2 \vee b+1=\sqrt2\\
b=-1-\sqrt2 \vee b=-1+\sqrt2

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4 years ago

Solve :1/1-x^a-b +1/1-x^b-a

Olegator [25]

Answer:

Step-by-step explanation:

$\frac{1}{1-x^{a-b}}+\frac{1}{1-x^{b-a}}\\\\\frac{1}{1-x^{b-a}}=\frac{1}{1-x^{-(a-b)}}=\frac{1}{1-\frac{1}{x^{a-b}}}\\=\frac{1}{\frac{x^(a-b)-1}{x^(a-b)}}=\frac{x^{a-b}}{x^{a-b}-1}\\\\=\frac{x^{a-b}}{-(1-x^{a-b})}=-\frac{x^{a-b}}{1-x^{a-b}}\\\\\frac{1}{1-x^{a-b}}+\frac{1}{1-x^{b-a}}=\frac{1}{1-x^{a-b}}-\frac{x^{a-b}}{1-x^{a-b}}\\\\=\frac{1-x^{a-b}}{1-x^{a-b}}=1$

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3 years ago

Rachel budgeted $76.50 for school clothes this is 0.45 of her total budget how much does Rachel have in her total budget

skad [1K]

Rachel has $170 in her total budget. You would set up a proportion to solve this. $\frac{76.50}{.45} = \frac{x}{1}$

6 0

4 years ago