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Alex
3 years ago
14

Is 5/7 equal than, less than, greater than

Mathematics
2 answers:
yanalaym [24]3 years ago
7 0

5 / 7  is equal to  10 / 14 , 85 / 119 , or  2.5 / 3.5 .

5 / 7  is less than  6 / 7,  0.714, or  501 / 700 .

5 / 7  is greater than  4 / 7,  -5 / 7,  zero,  or  49,999 / 70,000 .


suter [353]3 years ago
4 0
Multiply the numerator and denominator by the same number for= 5/7= 10/14= 20/28 5/7 < 5/6 < 5/5 5/7 > 5/8 ,5/9 in fractions. the larger the denominator the smaller the number hope this helps
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What is the area of the object above?
stepan [7]

Answer:

Option C

Step-by-step explanation:

You need to begin by separating the shape into two distinct rectangles. The larger one has dimensions 15 cm * 8cm, while the smaller one has dimensions 7cm * 5cm. Adding these together, you get 15*8+7*5=155 square centimeters, or option C. Hope this helps!

6 0
3 years ago
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Travelers who fail to cancel their hotel reservations when they have no intention of showing up are commonly referred to as no-s
notsponge [240]

Answer:

a) 0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) 0 is the most likely value for X.

Step-by-step explanation:

For each traveler who made a reservation, there are only two possible outcomes. Either they show up, or they do not. The probability of a traveler showing up is independent of other travelers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

No-show rate of 10%.

This means that p = 0.1

Four travelers who have made hotel reservations in this study.

This means that n = 4

a) What is the probability that at least two of the four selected will turn to be no-shows?

This is P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486

P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036

P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001

P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0486 + 0.0036 + 0.0001 = 0.0523

0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) What is the most likely value for X?

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561

P(X = 1) = C_{4,1}.(0.1)^{1}.(0.9)^{3} = 0.2916

P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486

P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036

P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001

X = 0 has the highest probability, which means that 0 is the most likely value for X.

7 0
3 years ago
4(5f + 9)
Marina86 [1]

Answer: hopes this helps i spent a lot of time on it !!!:)lol

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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