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Lady_Fox [76]
8 months ago
13

Select the correct answer. What is the range of the function f(x) = -4\x+ 11 - 5? A. (-4,-5) B. [-5,-) OC. (-4,-) OD. (-2,-4] Re

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Mathematics
1 answer:
Y_Kistochka [10]8 months ago
3 0

We are given the following function:

f(x)=-4\lvert x+1\rvert-5

This function is equivalent to the function:

g(x)=-4\lvert x+1\rvert

Together with a translation 5 units in the negative direction of the "x" axis. Since the range of g(x) is all the values of "y" that are smaller or equal to zero, if we translate 5 units in the negative direction of the y-axis the range is:

R(f(x))=\mleft\lbrace y\parallel y\mright?\le5\rbrace

or in interval notation:

R(f(x))=(-\infty,-5\rbrack

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I WILL GIVE BRAINILY... I need the full equation ASAP THANK YOU!!
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Answer:

y=\frac{9}{10} x-\frac{7}{5}

Step-by-step explanation:

points on the line:- (-4,-5)&(6,4)

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✄┈┈┈┈┈┈┈┈┈┈┈┈┈┈«

┍━━━━ ⋆⋅☆⋅⋆ ━━━━┑

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6 0
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Round up to the nearest hundredth
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x^2+3x-5=0\\\\a=1;\ b=3;\ c=-5\\\\b^2-4ac=3^2-4\cdot1\cdot(-5)=9+20=29\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-3-\sqrt{29}}{2\cdot1}=\dfrac{-3-\sqrt{29}}{2}\approx-4.19\\\\x_2=\dfrac{-3+\sqrt{29}}{2\cdot1}=\dfrac{-3+\sqrt{29}}{2}\approx1.19
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