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frozen [14]
3 years ago
7

If d is the midpoint of CE, CD=X+7,AND CE=5×-1 DETERMINE EACH MISSING VALUE

Mathematics
1 answer:
meriva3 years ago
7 0

The midpoint splits a segment in two sub-segments of equal length. This means that CD and DE are both half of CE

So, you have

CE = 2CD

Plug in the expressions you're given:

5x-1 = 2(x+7) \iff 5x-1 = 2x + 14 \iff 3x = 15 \iff x = 5

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2 Which of the following polynomials is not written in standard form?
Varvara68 [4.7K]

Answer:

3

Step-by-step explanation:

Standard form is written in the order of the exponent <em>on</em><em> </em><em>a</em><em> </em><em>variable</em> from highest to lowest.

#1 exponents go 2, 1 , then zero. So, this is standard form.

#2 exponents go 2 then zero, so this is standard form.

#3 exponents go 1 then 2 then zero, so this is <em><u>not</u></em> in standard form.

#4 exponents go 3 to 2 to 1, so this is still in standard form.

hope this helps!

8 0
3 years ago
800 is 10 times as much as
Anon25 [30]
80 because 800= 10 x 8
3 0
3 years ago
If a+b+c=16 and a^2+b^2+c^2=90 then find the value a^3+b^3+c^3-3abc
grin007 [14]

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)\\(16)^2=90+2(ab+bc+ca)\\256-90=2(ab+bc+ca)\\166/2=ab+bc+ca\\83=ab+bc+ca\\a^3-b^3-c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))\\16(90-(83))\\16(7)\\=112

3 0
3 years ago
according to the fundamental theorem of algebra , how many zeros does the polynomial below have x^4 +5x^3+10x^2+20x+24
Vinil7 [7]

Answer:

4

Step-by-step explanation:

the Fundamental Theorem of Algebra states that for any polynomial of degree n, there are n roots, some of which may be complex

The polynomial shown is of degree 4 ( highest exponent of x )

Hence the polynomial has 4 roots/ zeros



8 0
3 years ago
Read 2 more answers
Help me out a little
konstantin123 [22]
I believe your answer is (1,5)

I graphed the equations and the ordered pairs and (1,5) is the only point that fell on both of the shaded areas.

hope this helps !!
8 0
3 years ago
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