Question

If d is the midpoint of CE, CD=X+7,AND CE=5×-1 DETERMINE EACH MISSING VALUE

Answer 1

The midpoint splits a segment in two sub-segments of equal length. This means that CD and DE are both half of CE

So, you have

$CE = 2CD$

Plug in the expressions you're given:

$5x-1 = 2(x+7) \iff 5x-1 = 2x + 14 \iff 3x = 15 \iff x = 5$