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V125BC [204]
3 years ago
8

The perimeter of a square is 52 meters. What is it area.

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer:

169 meters

Step-by-step explanation:

52/4=13 (since it's a square you divide it by 4 because the sides are equal, so each side is 13 meters)

13^2=169 (to find the area you square the length of each side)

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At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel
Alexeev081 [22]
Use Law of Cooling:
T(t) = (T_0 - T_A)e^{-kt} +T_A
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
42 = (80-20)e^{-3k} +20 \\  \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\  \\ k = -\frac{1}{3} ln (\frac{11}{30})

Substituting k back into cooling equation gives:
T(t) = 60(\frac{11}{30})^{t/3} + 20

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\  \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80
Solve for x:
x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80
Sub back into original cooling equation, x = T(t)
-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20
Solve for t:
60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3}  = 60 \\  \\  (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\  \\  \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\  \\ \\  t = 4.959

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
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3 years ago
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DENIUS [597]

Answer:

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Answer:

It's linear

Step-by-step explanation:

Linear equations have no exponents higher than a 1, which is the case for this equation cause if there's no exponent it's cause it's just a 1. Non-linear has a exponent higher than a 1, ex. x^{2}

3 0
3 years ago
What is the true solution to the equation below? ln e^lnx^2=2 ln 8?
arlik [135]
x\ \textgreater \ 0\\\\
\ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8\\
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6 0
3 years ago
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If you flip a coin and roll a
worty [1.4K]

Answer: 1/12

Step-by-step explanation:

Your outcome, 2H, divided by the total size of the output set. Thus gives you probability 1/12

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