Its factors would be
(x+2)*(x-1)*(x+0)
x^2 +x -2
x^3 + 0 + x^2 + 0 -2x +0
Equation: x^3 + x^2 -2x
f(2) = 8 + 4 -4
2x^3 + 2x^2 -4x +0
f(2) = 16 + 8 -8
3x^3 + 3x^2 -6x +0
f(2) = 24 +12 -12
4x^3 + 4x^2 -8x +0
f(2) = 32 +16 -16
So, the equation is:
4x^3 + 4x^2 -8x = 0
<span>Find the inverse of the given function.
f(x) = -1/2√x + 3, x ≥ -3
I will have to assume that you meant f(x) = -(1/2)sqrt(x) + 3. If you actually meant f(x) = -(1/2)sqrt(x+3), then obviously the correct result would be different.
1. Replace "f(x)" by "y:" y </span>= -(1/2)sqrt(x) + 3
2. Interchange x and y: x = -(1/2)sqrt(y) + 3
3. Solve for y: x-3=-(1/2)sqrt(y), so that 2(3-x)= sqrt(y) and y=+sqrt(2[3-x])
4. Replace "y" with
-1
f (x) = sqrt(2[3-x])
Here, there are restrictions on x, since the domain of the sqrt function does not include - numbers. The domain here is (-infinity,3]
Answer:
-14 or -2
Step-by-step explanation:
-8+-6= -14
-8+6 = -2
Answer: The expression is 7/2.
Answer:
-1, |-2|, |-3|, |3.5|, |3²|
Step-by-step explanation:
- Calculate the absolute value (the absolute value of any number is always positive): 3, 3², 2 , 3.5, -1
- Calculate the exponents : 3, 9, 2 , 3.5, -1
- Put in order least to greatest : -1, |-2|, |-3|, |3.5|, |3²|