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suter [353]
3 years ago
6

f one plane is flying at 40 mph while another is flying at 100 mph, and they are 200 miles apart and flying directly towards eac

h other, how long will it take them to meet?
Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

t = 1 3/7 hours

Step-by-step explanation:

For plane 1

distance = rate *t

d1 = 40 *t


For plane 2

distance = rate * time

d2 = 100 * t


We know that d1+d2 = 200  (the planes will meet)

We know that the times will be the same because the leave at the same time.

Substitute in d1 =40t and d2 = 100t into  d1+d2 = 200


d1+d2 = 200

40t + 100t = 200

Combine like terms

140t = 200

Divide each side by 140

140t/140 = 200/140

t= 200/140

t= 20/14

t = 10/7

t = 1 3/7 hours

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