Answer:
x = 7
42, 35, 7
Step-by-step explanation:
- EG = 5x+7
- EF = 5x
- FG = 2x-7
Point F is on line segment of EG, therefore EG = EF + FG
- 5x + 7 = 5x + 2x - 7
- 2x = 14
- x = 7
Then
- EG = 5*7 + 7 = 42
- EF = 5*7 = 35
- FG = 2*7 - 7 = 7
Answer:
-9/4, -0.75, -6/10, 5/3, 2.1
Step-by-step explanation:
This is a lot easier to figure out if you simplify the fractions and then change them to decimals
So -9/4 = -2 1/4 or -2.25
-0.75
-6/10 = -0.60
5/3 = 1 2/3 or 1.67
2.1
When you are ordering negatives, the biggest negative is the least. That is why -9/4 (-2.25) is the least number out of the five given.
The next one would be -0.75, because it is the second biggest negative fraction.
The next one is -0.60 because that is the 3rd biggest negative fraction (or the smallest because this is the last negative)
Now, because we're in the positives we start with 1.67, because it is smaller than the other number.
2.1 is our last number, so it is the greatest!
I hope this helped :)
Is is it a function Bcoz 4 and 0 has only one out. When you have one in and two out that's means is not a function.
Answer:
Step-by-step explanation:
To solve:
x - 8 = -20
Simply add +8 to both sides of the equation.
It becomes :
x - 8 +8 = -20 + 8
Note that, -8 + 8 will cancel out, and results to zero.
Therefore the equation becomes :
x = -20 + 8
x = -12.
Hope this helped!
(a) You can parameterize <em>C</em> by the vector function
<em>r</em><em>(t)</em> = (<em>x(t)</em>, <em>y(t)</em> ) = <em>P</em> (1 - <em>t </em>) + <em>Q</em> <em>t</em> = (2 - 2<em>t</em>, 7<em>t</em> )
where 0 ≤ <em>t</em> ≤ 1.
(b) From the above parameterization, we have
<em>r</em><em>'(t)</em> = (-2, 7) ==> ||<em>r</em><em>'(t)</em>|| = √((-2)² + 7²) = √53
Then
d<em>s</em> = √53 d<em>t</em>
and the line integral is
(c) The remaining integral is pretty simple,
