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3 years ago

Center (7,-9); radius 3

1 answer:

6 0

The general form for a circle is (x - h)^2 + (y - k)^2 = r^2, where (h, k) represent the centre and r represent the radius.

With centre (7, -9) and radius 3, we can simply substitute it into our form:

(x - 7)^2 + (y + 9)^2 = 3^2
(x - 7)^2 + (y + 9)^2 = 9

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When a particular type of thumbtack is dropped, it will land point up (A flat-top thumbtack resting on its flat top) or point

erma4kov [3.2K]

Answer:

0.48

0.52

Yes

Step-by-step explanation:

Result of experiment :

Point up = 48

Point down = 52

Total number of trials = 100

Recall :

Experimental probability = number of outcomes / number of trials

1.)

P(Landing point up) = 48 / 100 = 0.48

2.)

P(Landing point down) = 52 / 100 = 0.52

3.)

The same result will not occur has the outcomes of trials aren't fixed.

4.) Yes, nearly the same result could occur on the second trial, as the number of possible outcubes are just 2 and the number if trials is high.

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3 years ago

What is the square root of 129876? :)

icang [17]

Answer:

360.383129461

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a

Anarel [89]

Answer:

Average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: $f(x)= x^2-x-1$

The formula used to find average rate of change is:

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}$

We have, a = -1 and b = 1

Finding f(b) when b=1

$f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1$

Now, finding f(a), when a= -1

$f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1$

Now, putting values and finding average rate of change

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1$

So, average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

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3 years ago

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ElenaW [278]

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3 years ago

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ololo11 [35]

Answer:

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Step-by-step explanation:

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