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lara [203]
3 years ago
9

Find an equation for the perpendicular bisector of the line segment whose endpoints are (-5,5) and -9,-9

Mathematics
1 answer:
cestrela7 [59]3 years ago
5 0

Answer:

y= 3.5x+22.5

Step-by-step explanation:

The standard equation of a line a expressed as y = MX+c

m is the slope

c is the y-intecept

Get the slope

m = y2-y1/x2-x1

m = -9-5/-9+5

m = -14/-4

m = 7/2

Get the y- intercept

Substitute any of the point say (-5,5) and m = 7/2 into the equation y = MX+c

5 = 7/2(-5)+c

5= -35/2+c

5 =-17.5+c

c = 5+17.5

c =22.5

Get the required equation

Recall that y = MX+c

y= 3.5x+22.5

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7 0
3 years ago
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Rewrite the quadratic function in vertex form.<br> Y=2x^2+4x-1
Fantom [35]

Answer:

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Step-by-step explanation:

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We have

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5 0
3 years ago
1.
lisov135 [29]

2 = X = -1

2

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= 7x + 8 = 3x + 6

Rearrange the terms

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CLT

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x = -2

4

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2

4 0
1 year ago
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Answer:

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