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Levart [38]
3 years ago
9

A shipping company handles containers in three different sizes: (1) 27 ft3 (3 × 3 × 3), (2) 125 ft3, and (3) 512 ft3. Let Xi (i

= 1, 2, 3) denote the number of type i containers shipped during a given week. With μi = E(Xi) and σi2 = V(Xi), suppose that the mean values and standard deviations are as follows: ?1 = 230 ?2 = 240 ?3 = 120?1 = 11 ?2 = 12 ?3 = 7(a) Assuming that X1, X2, X3 are independent, calculate the expected value and variance of the total volume shipped. [Hint: Volume = 27X1 + 125X2 + 512X3.]expected value ft3variance ft6(b) Would your calculations necessarily be correct if the Xi's were not independent? Explain.The expected value would not be correct, but the variance would be correct. Neither the expected value nor the variance would be correct. The expected value would be correct, but the variance would not be correct.Both the expected value and the variance would be correct.
Mathematics
1 answer:
inysia [295]3 years ago
6 0

Answer:

Sorry I have no idea lol. I hope you find your answer soon.

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Answer:

Fri: 4 hybrids ,9 total

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5 0
3 years ago
Find T​, N​, and kappa for the plane curve Bold r left parenthesis t right parenthesis equalsleft parenthesis 7 Bold cos t plus
pickupchik [31]

Answer:

Step-by-step explanation:

r(t) = (7 cost + 7t sin t)i + (7 sin t - 7t cos t)j

\frac{d \bar r t}{dt} =(7\frac{d}{dt}\cos t + 7\frac{d}{dt} (t \sin t)i+(7\frac{d}{dt} \sin t-7\frac{d}{dt}  t \cos t)j

=(7(-\sin t)+7(1* \sin t+t \cos t))i+(7 \cost -7(1*\cos t - t \sin t))j\\\\=7((-\sin t+\sin t+t \cos t)i+(\cos t-\cos t+t \sin t)j)\\\\=7((t\cos t)i+(t\sin t)j)

\bar r'(t)=\frac{d \bar r t}{dt} =(7t\cos t)i+(7t\sin t)j---(1)\\\\11\bar r(t)=\sqrt{(7t\cos t)^2+(7t\sin t)^2}\\\\=\sqrt{49t^2(\cos^2t+\sin^2 t)}  \\\\=7t

\bar T (t)=\frac{\bar r'(t)}{11\bar r(t)11} =\frac{(7t\cos t)i+(7t\sin t)j}{7t} \\\\\barT(t)=(\cos t)i+(\sin t)j

\bar T'(t)=\frac{d}{dt} (\cos t)i+\frac{d}{dt} (\sin t) j\\\\\bar T'(t)=(-\sin t)i+(\cos t)j---(2)\\\\11\bar T'(t)=\sqrt{(-\sin t)^2+(\cos t)^2} \\\\=\sqrt{\sin^2t+\cos^2t} \\\\=1

\bar N(t)=\bar T'(t)=\frac{(-\sin t)i+(\cos t)j}{(1)} \\\\ \large \boxed {\bar N(t)=(-\sin t)i+(\cos t)j}

K(t)=\frac{|\b\r T'(t)|}{\bar r (t)|} \\\\=\frac{|-\sin t i+\cos t j|}{|7t\cos t +7t \sin t j|}

Using eq (1) and (2)

K(t)=\frac{\sqrt{(-\sin t)^2+(\cos t)^2} }{\sqrt{(7t\cos t)^2+(7t\sin t)^2} }\\\\=\frac{\sqrt{\sin^2 t+\cos^2t} }{\sqrt{49t^2(\cos^2 t+\sin^2t)} }\\\\=\frac{\sqrt{1} }{\sqrt{49t^2\times 1} }  \\\\ \large \boxed {K(t)=\frac{1}{7t} }

7 0
3 years ago
PLEASE HELP AS SOON AS POSSIBLE Sunny earns $22.75 per week delivering newspapers. He worked as a delivery boy for 3 weeks. He a
Pavlova-9 [17]
Step 1 he had to multiply the $22.75 times 3 weeks it should have been 
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4 0
3 years ago
Help asap, with good explaination please
Verizon [17]

Answer:

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Step-by-step explanation:

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6 are in each layer but there are 12 going down layer by layer

so 10 times 6 equal 60

the actuall answer is 60

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3 years ago
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Diano4ka-milaya [45]

Answer:

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Step-by-step explanation: its goes on forever never stopping

3 0
3 years ago
Read 2 more answers
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