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iogann1982 [59]
3 years ago
10

Solve X^2 + 5x + 6 = 0

Mathematics
2 answers:
vesna_86 [32]3 years ago
7 0

x= -4/2 = -2

i believe this is it

Oduvanchick [21]3 years ago
6 0

Answer:

x = -2 or x = -3

Step-by-step explanation:

Solve for x over the real numbers:

x^2 + 5 x + 6 = 0

The left hand side factors into a product with two terms:

(x + 2) (x + 3) = 0

Split into two equations:

x + 2 = 0 or x + 3 = 0

Subtract 2 from both sides:

x = -2 or x + 3 = 0

Subtract 3 from both sides:

Answer: x = -2 or x = -3

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Answer:

y + 4 = -\frac{5}{6}(x - 8)

Step-by-step explanation:

In the Point-Slope Formula, y - y_1 = m(x - x_1),all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.

I am joyous to assist you anytime.

5 0
2 years ago
3. Taylor has a $30.00 gift card that she can
Andrew [12]
7 journals is the answer
4 0
3 years ago
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Evaluate the expression when a=14 and b=6. 5b/32a2
leonid [27]

Answer:

28/16071  as a decimal 0.00174226...

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
The mean number of words per minute (WPM) typed by a speed typist is 149 with a standard deviation of 14 WPM. What is the probab
Troyanec [42]

Answer:

78.81%

Step-by-step explanation:

We are given;

Population mean; μ = 149

Sample mean; x¯ = 147.8

Sample size; n = 88

standard deviation; σ = 14

Z-score is;

z = (x¯ - μ)/(σ/√n)

Plugging in the relevant values;

z = (147.8 - 149)/(14/√88)

z = -0.804

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6 0
2 years ago
A rocket is launched at 85 ft./s from a launch pad that’s 28 feet above the ground. which equation can be used to determine the
3241004551 [841]

Answer:

h(t)=-16t^2+85t+28  is equation of height of rocket.

Option D is correct.

Step-by-step explanation:

Given: A rocket is launched with speed 85 ft/s from a height 28  feet.

Launching a rocket follows the path of parabola. The equation of rocket should be parabolic.

Parabolic equation of rocket is

Formula: h(t)=\dfrac{1}2gt^2+v_0t+h_0

g ⇒ acceleration due to gravity (-32 ft/s)

v ⇒ Initial velocity (v_0=85\ ft/s)

h ⇒ Initial height (h_0=28\ feet)

h(t) ⇒ function of height at any time t

Substitute the given values into formula

h(t)=\frac{1}{2}(-32)t^2+(85)t+28

h(t)=-16t^2+85t+28

D is correct.

6 0
3 years ago
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