Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Answer:
y=4x+47
I wanted to wait for the person who originally said the answer but it's been a while and I kinda want the points. Sorry
Answer:
The average yearly drop in enrollment is 12.
Step-by-step explanation:
The average refers to the central value in a group of numbers and with the information provided, you can find the average by dividing the number of students that dropped out of the school by the number of years over which that ocurred:
number of students= 60
number of years= 5
60/5=12
According to this, the answer is that the average yearly drop in enrollment is 12.
1/7 of 42 is smaller. 47/7= 6 < 18 = 36/2
If this is correct the answer would be
y^2 + 0.1y + 0.0025
