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kaheart [24]
3 years ago
9

Weatherwise is a magazine published by the American Meteorological Society. One issue gives a rating system used to classify Nor

'easter storms that frequently hit New England and can cause much damage near the ocean. A severe storm has an average peak wave height of μ = 16.4 feet for waves hitting the shore. Suppose that a Nor'easter is in progress at the severe storm class rating. Peak wave heights are usually measured from land (using binoculars) off fixed cement piers. Suppose that a reading of 38 waves showed an average wave height of x= 17.3 feet. Previous studies of severe storms indicate that σ = 3.3 feet. Does this information suggest that the storm is (perhaps temporarily) increasing above the severe rating? Use α = 0.01. Solve the problem using the critical region method of testing (i.e., traditional method). (Round your answers to two decimal places.)test statistic = critical value = State your conclusion in the context of the application.Reject the null hypothesis, there is sufficient evidence that the average storm level is increasing.Reject the null hypothesis, there is insufficient evidence that the average storm level is increasing. Fail to reject the null hypothesis, there is sufficient evidence that the average storm level is increasing.Fail to reject the null hypothesis, there is insufficient evidence that the average storm level is increasing.Compare your conclusion with the conclusion obtained by using the P-value method. Are they the same?
Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0

Answer:

Step-by-step explanation:

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A rectangular bird sanctuary is being created with one side along a straight riverbank. the remaining three sides are to be encl
Mariana [72]
<span>2 km wide by 4 km long with the long side parallel to the river. So we can enclose a rectangular area using just 3 sides since the 4th side is provided free by the river. I'll use the variable L to represent the length of the side that's parallel to the river and W to represent the distance from the river that parallel side is. So the total perimeter of the fence will be 2W + L. Let's write down some equations. Area enclosed A = W * L Length of L expressed in terms of W 8 = 2W + L 8 - 2W = L Now substitute (8-2W) for L in the equation for the area. A = W * L A = W * (8-2W) A = 8W - 2W^2 Since we're looking for a maximum value, that will happen when the slope of the function is equal to 0. And the first derivative of the function tells you the slope at each point. So we need to calculate the first derivative. For simple functions such as what we have, we just need to multiply the coefficient of each term by the exponent of that term, then subtract 1 from the exponent. So let's calculate the first derivative of A = 8W - 2W^2 A = 8W - 2W^2 The term 8W has an implied exponent of 1 for W, so 8 * 1 = 8. And 1 - 1 = 0. So we have 8W^0. And since W^0 = 1, we have 8 as the 1st term of the derivative. The next term is -2W^2. So -2*2 = -4 and 2-1 = 1, giving us -4W^1. And we can get rid of the explicit exponent of 1 since that's assumed to exist giving us a term of -4W. So the first derivative becomes A' = 8 - 4W Now let's solve that equation for A' = 0. A' = 8 - 4W 0 = 8 - 4W 4W = 8 W = 2 So the ideal width of the fence is 2. And looking back at the equation 8 - 2W = L, we can calculate the length as 8 - 2*2 = 8 - 4 = 4, so the length of the fence is 4. So the dimensions of the sanctuary is 4 km parallel to the river and extended 2 km from the river for a total area of 4*2 = 8 km^2. To demonstrate that is the ideal size, let's show that if the width is either smaller or larger, then we'll have a smaller sanctuary. Let's show the smaller case. For this we'll introduce a variable called "e" which represents a very tiny, but non-zero amount of length. So we'll call the width W+e or 2+e and the length will be 8 - 2*(2+e) = 8 - 4 - 2e = 4 - 2e So the area is A = WL A = (2+e)(4-2e) A = 8 -4e + 4e - 2e^2 A = 8 - 2e^2 And as you can see, as long as e is none zero the area will be smaller than 8 km^2. Now let's try a width that's less than 2 by a tiny amount. Our width is now (2-e) and that makes our length (4+2e). So A = WL A = (2-e)(4+2e) A = 8 + 4e -4e - 2e^2 A = 8 - 2e^2 And once again, if the width is slightly smaller so the length is slightly longer, the area is once again, slightly smaller. So the absolute best side for the sanctuary is 2 km wide by 4 km long.</span>
6 0
3 years ago
Help please I’m having trouble
tangare [24]

Answer:

22

Step-by-step explanation:

6(3^2+2)=66

66/2= 22

8 0
3 years ago
Read 2 more answers
In a University of Wisconsin (UW) study about alcohol abuse among students, 100 of the 40,858 members of the student body in Mad
dimaraw [331]

Answer:

a) The population is 40,858 students and the sample is 100.

b) No

Step-by-step explanation:

a) The population would be the 40,858 members of the student body. Since we are only applying the questionnaire to 100 students, the sample would be 100.

b) 29% of the students answered "zero" to the question on how many days in the past week they consumed at least one alcoholic drink. This means that 29 out of 100 students gave this answer. However, this doesn't mean that 29% of the entire population of UW would give this response. Why is that? Because our sample is very small so it might not be representative of the whole population. Equally, the results from such a sample cannot be exactly the same results we would get from an entire population.

7 0
3 years ago
This also please and thank you for those who do decide to help me
alex41 [277]
240 for # 2 because 6 times 4 times 10 is equal to 240



I am still working on others
4 0
3 years ago
7. I am currently 5 times as old as my daughter. In 6 years from now. I will be three times as old she will be then. Find our cu
xxTIMURxx [149]

Answer:

Daughter is 6 , mother is 30.

Step-by-step explanation:

5 0
2 years ago
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