Which of the objects shown below could be sliced to create square cross-sections?
1 answer:
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Answer:
The 90th percentile for the distribution of the total contributions is $6,342,525.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For sums of size n, the mean is and the standard deviation is
In this question:
The 90th percentile for the distribution of the total contributions
This is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. Then
By the Central Limit Theorem
The 90th percentile for the distribution of the total contributions is $6,342,525.
Answer:
The number of people who paid $ 12 for reserved seat is 5,000
The number of people who paid $ 4 for general seat is 29,000
Step-by-step explanation:
Given as :
The total number of people attending a ballgame = 34,000
The total receipt of the ticket's seat = $ 176,000
The amount pad for reserved seat = $ 12
The amount paid for general admission = $ 4
Let The number of people for reserved seat = r
And The number of people for general admission = g
Now, According to question
The total number of people attending a ballgame = The number of people for reserved seat + The number of people for general admission
or, r + g = 34,000 ...........1
The total receipt of the ticket's seat = The amount pad for reserved seat × The number of people for reserved seat + The amount paid for general admission × The number of people for general admission
Or, $ 12 × r + $ ×4 g = $ 176,000 .........2
or, $ 12 × ( r + g ) = $ 12 × 34000
Or, $ 12 r + $ 12 g = $ 408,000
Solving equation
( $ 12 r + $ 12 g ) - ($ 12 r + $ 4 g ) = $ 408,000 - $ 176,000
Or, ( $ 12 r - $ 12 r ) + ( $ 12 g - $ 4 g ) = $ 232,000
Or 0 + 8 g = 232,000
∴ g =
I.e g = 29,000
So , The number of people for general admission = g = 29,000
Put the value of g in Eq 1
I.e r + g = 34,000
or , r = 34,000 - g
∴ r = 34000 - 29000
I.e r = 5,000
So, The number of people for reserved seat = r = 5,000
Hence The number of people who paid $ 12 for reserved seat is 5,000
And The number of people who paid $ 4 for general seat is 29,000 Answer