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torisob [31]
3 years ago
13

Under his cell phone plan, Henry pays a flat cost of $63.50 per month and $5 per gigabyte. He wants to keep his bill at $77.50 p

er month. How many gigabytes of data can he use while staying within his budget?
Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

2

Step-by-step explanation:

77.50 - 63.50 = 14

per gigabyte $5 + 5 =10

so answer is 2

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Which scenario represents a proportional relationship?
kirza4 [7]

Answer:

The answer should be B

Step-by-step explanation:

I hope this helps! Let me know if I am wrong.

4 0
3 years ago
WILL GIVE U BRAINLIEST ♡ Rationalize the denominator of fraction with numerator square root of -36 divided by (2-3i)+(3+2i)
Dmitriy789 [7]

Answer:

-  \frac{3}{13}  +  \frac{15i}{13}

Step-by-step explanation:

\frac{ \sqrt{ - 36} }{(2 - 3i) + (3 + 2i)}

Set up equation

Step 1: Simplify

\frac{6i}{5 - i}

Step 2:Multiply by conjugate

\frac{6i}{5 - i}  \times  \frac{5 + i}{5 + i}

Step 3:Simplify

\frac{30i + 6 {i}^{2} }{ {i}^{2} - 5 {}^{2}  }

We can reduce this and we must make the imaginary number and real number serpate equations.

-  \frac{6}{26}  +  \frac{30i}{26}

Reduce each by 2

- \frac{3}{13}  +  \frac{15i}{13}

7 0
3 years ago
Another house is sold for £283,392
Dmitry_Shevchenko [17]

Answer:

the price paid is  £288,000

Step-by-step explanation:

The computation of the price paid is shown below:

Sale of the another house is £283,392

Since the another house would be 1.6% less than the price paid

So, the price paid would be

=  £283,392 × 100 ÷ (100 - 1.6%)

=  £283,392 × 100 ÷ 98.4

=  £288,000

Hence, the price paid is  £288,000

8 0
3 years ago
(PLEASE ANSWER!!) a college student completed some courses worth 4 credits and some courses worth 3 credits. the student earned
Ierofanga [76]

The college student took 13 courses of 3 credit hours.

Step-by-step explanation:

Given,

Total credits = 59

Total courses = 18

Let,

Number of 3 credit hour courses = x

Number of 4 credit hour courses = y

According to given statement;

x+y=18     Eqn 1

3x+4y=59   Eqn 2

We will eliminate y to find the number of 3 credit hour courses, therefore,

Multiplying Eqn 1 by 4

4(x+y=18)\\4x+4y=72\ \ \ Eqn\ 3

Subtracting Eqn 2 from Eqn 3

(4x+4y)-(3x+4y)=72-59\\4x+4y-3x-4y=13\\x=13

The college student took 13 courses of 3 credit hours.

Keywords: linear equation, subtraction

Learn more about linear equations at:

  • brainly.com/question/10708697
  • brainly.com/question/10710410

#LearnwithBrainly

5 0
4 years ago
HELPPPPP PLEASEEEEE
timama [110]

Answer:

19938383

Step-by-step explanation:

5 0
3 years ago
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