Step-by-step explanation:
(2b-3)/(b-2)(b+2) = 3b(b-2)/(b+2)(b-2)
2b²+4b-3b-6/b²-4=3b²-6b/b²-4
2b²+b- 6= 3b²-6b
move square to square unknown to unknown
-b²+7b-6/b²-4
i also dk this is true or false
You would substitute the given value of “y” into the equation of -14x+y=16
-14x+5x-2=16
Then you would solve for “x”
x=2
You would then substitute the value of “x” into the equation to solve for “y”
y=5(2)-2
Which would then give you a value for “y”
y=12
So the answer is (2,12)
Answer:
x = -5 and y = 3
Step-by-step explanation:
There are two equations :
3x − 2y = −21 ....(1)
2x + 5y = 5 ......(2)
Multiply equation (1) by 2 and equation (2) by 3.
6x - 4y = -42 ...(3)
6x + 15y = 15 ....(4)
Subtract equation (4) from (3) :
6x - 4y - (6x + 15y) = -42 -15
-4y -15y = -57
-19y = -57
y = 3
Put y = 3 in equation (2) :
2x + 5(3) = 5
2x = 5-15
2x = -10
x = -5
So, the value of x is (-5) and y = 3.