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3 years ago

What is a over b = -2

1 answer:

3 0

A / b = -2

Take note:

to have a quotient with at negative sign, both a & b must have opposites signs. a can be a positive number while b is a negative number or vice versa. If both a and b have the same sign, its quotient will be a positive number.

Let us disregard the sign.
To arrive at the answer of 2, a must be twice the amount of b. meaning a = 2b.

For example: look for a if b is equal to 2. a = 2(2) ; a = 4.
a / b = 2
4 / 2 = 2
2 = 2

Now, we consider the sign of both numbers. a can be 4 while b can be -2 OR vice versa.

a / b = -2
4 / -2 = -2 or -4 / 2 = -2

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Help me solve this having trouble.

pishuonlain [190]

sin x= opposite / hypotenuse.
opposite=4
hypotenuse=5

sin x=4/5
x=arc sin (4/5)=53.13º

Answer: x=53.13º

7 0

4 years ago

1-cot^2a+cot^4a=sin^2a(1+cot^6a) prove it.

aliina [53]

Step-by-step explanation:

We have

1-cot²a + cot⁴a = sin²a(1+cot⁶a)

First, we can take a look at the right side. It expands to sin²a + cot⁶(a)sin²(a) = sin²a + cos⁶a/sin⁴a (this is the expanded right side) as cot(a) = cos(a)/sin(a), so cos⁶a = cos⁶a/sin⁶a. Therefore, it might be helpful to put everything in terms of sine and cosine to solve this.

We know 1 = sin²a+cos²a and cot(a) = cos(a)/sin(a), so we have

1-cot²a + cot⁴a = sin²a+cos²a-cos²a/sin²a + cos⁴a/sin⁴a

Next, we know that in the expanded right side, we have sin²a + something. We can use that to isolate the sin²a. The rest of the expanded right side has a denominator of sin⁴a, so we can make everything else have that denominator.

sin²a+cos²a-cos²a/sin²a + cos⁴a/sin⁴a

= sin²a + (cos²(a)sin⁴(a) - cos²(a)sin²(a) + cos⁴a)/sin⁴a

We can then factor cos²a out of the numerator

sin²a + (cos²(a)sin⁴(a) - cos²(a)sin²(a) + cos⁴a)/sin⁴a

= sin²a + cos²a (sin⁴a-sin²a+cos²a)/sin⁴a

Then, in the expanded right side, we can notice that the fraction has a numerator with only cos in it. We can therefore write sin⁴a in terms of cos (we don't want to write the sin²a term in terms of cos because it can easily add with cos²a to become 1, so we can hold that off for later) , so

sin²a = (1-cos²a)

sin⁴a = (1-cos²a)² = cos⁴a - 2cos²a + 1

sin²a + cos²a (sin⁴a-sin²a+cos²a)/sin⁴a

= sin²a + cos²a (cos⁴a-2cos²a+1-sin²a+cos²a)/sin⁴a

= sin²a + cos²a (cos⁴a-cos²a+1-sin²a)/sin⁴a

factor our the -cos²a-sin²a as -1(cos²a+sin²a) = -1(1) = -1

sin²a + cos²a (cos⁴a-cos²a+1-sin²a)/sin⁴a

= sin²a + cos²a (cos⁴a-1 + 1)/sin⁴a

= sin²a + cos⁶a/sin⁴a

= sin²a(1+cos⁶a/sin⁶a)

= sin²a(1+cot⁶a)

8 0

3 years ago

What is the equation of the tangent line passing through the point (0, 3) of the graph of the function f(x) = x2 − 2x + 3?

Sergeeva-Olga [200]

Answer:

y = -2x + 3

Step-by-step explanation:

The given equation is:

$f(x)=x^2-2x+3$

First we need to find the slope of the tangent line. This can be done by finding the derivative of the given function.

$f'(x)=2x-2$

Slope of the tangent will be the value of the derivative at the given point. So the slope of tangent is:

$f'(0)=2(0)-2=-2$

Now we have slope of the tangent line and a point (0, 3) on the tangent. The point (0,3) is the y-intercept of the tangent line. So we can use slope-intercept form to directly write the equation of the line.

The slope intercept form of an equation is:

y = mx + c

where m is the slope and c is the y-intercept.

Using the values: m = -2 and c = 3, we get:

y = -2x + 3

This equation represents the tangent line

8 0

4 years ago

WILL GIVE BRAINLIEST!!!!!!

ankoles [38]

Answer:

d??? i think

Step-by-step explanation:

4 0

3 years ago

Which of the following would represent the first step in simplifying the problem 7+56(6-2) divided by 2

Gennadij [26K]

Answer:

Think about PEMDAS, Whatever is in parentheses you solve that first. (6-2) which will be 4, you'll do 7+65*4 and find your answer. And divide by 2 at the end.

Hope this help

Step-by-step explanation:

5 0

3 years ago

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