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3 years ago

Please help I need it so bad

Mathematics

1 answer:

Elis [28]3 years ago

6 0

Answer:

y ≤ 3x - 2 and 4x + y ≥2

Step-by-step explanation:

We can easily solve this problem by using a plotting tool or any graphing calculator.

We test each case, until we arrive to the correct option

Case 1

y ≤ 3x - 2 and 4x + y ≥2

Correct Option.

Please see attached image for graph

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Mark the statements that are true. A. An angle that measures π/4 radians also measures 45°. B. An angle that measures 180° also

FinnZ [79.3K]

Answer:

TRUE: A, B, C

False: D

Step-by-step explanation:

A full circle of 360° has a radian measure of 2π radians. The relationship is proportional, so π radians is 180°.

A. An angle that measures π/4 radians also measures 45°. TRUE

45° × π/180° radians = π/4 radians

B. An angle that measures 180° also measures π radians. TRUE

180° × π/180° radians = π radians

C. An angle that measures 60° also measures π/3 radians. TRUE

60° × π/180° radians = π/3 radians

D. An angle that measures π/3 radians also measures 30°. FALSE

30° × π/180° radians = π/6 radians

5 0

2 years ago

What is the explicit formula for the sequence 7,2,-3,-8,-13

eduard

You could say that a(n) = 12 - 5n .

Then ...

a(1) = 12 - 5 = 7
a(2) = 12 - 10 = 2
a(3) = 12 - 15 = -3
and so on.
So it seems to work.

8 0

2 years ago

Read 2 more answers

Find the equation of a line, in slope-intercept fotm of a line that passes through the point (9,2) and is perpendicular to the l

cricket20 [7]

Considering the definition of perpendicular line, the equation of of perpendicular line is y= - $\frac{1}{2}$ x + $\frac{13}{2}$ .

<h3>Linear equation</h3>

A linear equation o line can be expressed in the form y = mx + b.

where

x and y are coordinates of a point.

m is the slope.

b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.

<h3>Perpendicular line</h3>

Perpendicular lines are lines that intersect at right angles or 90° angles. If you multiply the slopes of two perpendicular lines, you get –1.

<h3>Equation of perpendicular line in this case</h3>

In this case, the line is 2x-y=8. Expressed in the form y = mx + b, you get:

-y=8 - 2x

y= (-2x +8)÷ (-1)

y= 2x -8

If you multiply the slopes of two perpendicular lines, you get –1. In this case, the line has a slope of 2. So:

2× slope perpendicular line= -1

slope perpendicular line= (-1)÷ (2)

<u><em>slope perpendicular line= -</em></u> $\frac{1}{2}$

So, the perpendicular line has a form of: y= - $\frac{1}{2}$ x + b

The line passes through the point (9, 2). Replacing in the expression for perpendicular line:

2= (- $\frac{1}{2}$ )× 9 + b

2= - $\frac{9}{2}$ + b

2+ $\frac{9}{2}$ = b

Finally, the equation of of perpendicular line is y= - $\frac{1}{2}$ x + $\frac{13}{2}$ .

Learn more about perpendicular line:

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6 0

1 year ago

Subtract 1/6a + 3 from 1/3a -5

pishuonlain [190]

1/3a - 5 - (1/6a + 3)

= 1/3a - 5 - 1/6a - 3

= 1/6a - 8 Answer

6 0

3 years ago

The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the imprope

lesya692 [45]

(1) D

$L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt$

Integrate by parts, taking

$u = t \implies \mathrm du=\mathrm dt$

$\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}$

Then

$L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}$

(2) A

$L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}$

7 0

3 years ago