Answer:
a.) April has 30 days
If you for option No.2, you would have:
[day, amount($)]
1, 0.01
2, 0.02
3, 0.04
4, 0.08
5, 0.16
6, 0.32
7, 0.64
8, 1.28
9, 2.56
10, 5.12
11, 10.24
12, 20.48
13, 40.96
14, 81.82
15. 163.48
16, 327.68
17, 655.36
18, 1310.72
19, 2621.44
20, 5242.88
21, 10,485.76
22, 20,971.52
23, 41,943.04
24, 83,886.08
25, 167,772.16
26, 335,544.32
27, 671,088.64
28, 1,342,177.28
29, 2,684,354.56
30, 5,368,709.12
Option 2 grants you more than 5 times as much as Option A and is therefore obviously better.
b.) A diagram would show first a slow rise, than a steeper and steeper rise, then would almost growvertically. exponential growth
#coronatime
The most elegant form to describe the given numbers would simply be
$=1*2^x
You start with one, eich doubles after a day (x=1). x is the number of days and how often you multiply by 2
c.) Wasn't sure without calculating, but I guessed Opt.2, because it seemed that one should be tricked into choosing Opt.1
Have a nice day
Brainliest would be appreciated
If there are questions left, feel free to ask them
2/3 plus 2/3 is 4/3 or 16/12
we have 12 and 9/12 subtracted by 16/12 thats is the answer
11 7/12 :)
Answer:
3 hours and 20 minutes
Step-by-step explanation:
Answer: this is hard I hate math sorry
Step-by-step explanation:
:(
Answer:
![2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36](https://tex.z-dn.net/?f=2%28a%5E3%2Bb%5E2%2B11%29%2B1%283%2Ba%5E3%2Bb%2B11%29%3D3a%5E3%2B2b%5E2%2Bb%2B36)
Step-by-step explanation:
I assume that you need simplification of the given expression.
The given expression is:
![2(a^3+b^2+11)+1(3+a^3+b+11)](https://tex.z-dn.net/?f=2%28a%5E3%2Bb%5E2%2B11%29%2B1%283%2Ba%5E3%2Bb%2B11%29)
Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,
![2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14](https://tex.z-dn.net/?f=2%28a%5E3%2Bb%5E2%2B11%29%3D2%5Ctimes%20a%5E3%2B2%5Ctimes%20b%5E2%2B2%5Ctimes%2011%5C%5C2%28a%5E3%2Bb%5E2%2B11%29%3D2a%5E3%2B2b%5E2%2B22%5C%5C%5C%5C1%283%2Ba%5E3%2Bb%2B11%29%3D1%5Ctimes%203%2B1%5Ctimes%20a%5E3%2B1%5Ctimes%20b%2B1%5Ctimes%2011%5C%5C1%283%2Ba%5E3%2Bb%2B11%29%3D3%2Ba%5E3%2Bb%2B11%3Da%5E3%2Bb%2B14)
Therefore,
is equal to:
![2a^3+2b^2+22+a^3+b+14](https://tex.z-dn.net/?f=2a%5E3%2B2b%5E2%2B22%2Ba%5E3%2Bb%2B14)
Now, combining like terms using the commutative property of addition, we get:
![=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36](https://tex.z-dn.net/?f=%3D%282a%5E3%2Ba%5E3%29%2B2b%5E2%2Bb%2B%2822%2B14%29%5C%5C%3D3a%5E3%2B2b%5E2%2Bb%2B36)
Therefore, the simplified form is ![3a^3+2b^2+b+36](https://tex.z-dn.net/?f=3a%5E3%2B2b%5E2%2Bb%2B36)