A "slow" clock falls behind at the same rate every hour. It is set to the correct time at 4a;00 AM. When the clock shows 5:00 AM
1 answer:
You might be interested in
The first step to solving this is to plug in 4 and 3/4 where p and q are.
4(
+ 
) - 3
Now we can start solving this expression by adding the fractions together
4 x
- 3
Next you will reduce the numbers with 4
5 - 3
Finally,, subtract the numbers to get your final answer
2
This means that the correct answer to your question is 2.
Let me know if you have any further questions
:)
4(
Now we can start solving this expression by adding the fractions together
4 x
Next you will reduce the numbers with 4
5 - 3
Finally,, subtract the numbers to get your final answer
2
This means that the correct answer to your question is 2.
Let me know if you have any further questions
:)