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lubasha [3.4K]
3 years ago
13

What is the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.3? round yo

ur answer to the nearest tenth of percent
a.29.4%
b.27.4%
c.26.4%
d.28.4%
Mathematics
1 answer:
elena55 [62]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Use the table of Z-score, considering it represnts the probability of data to the left of Z-value, the needed probability would be the subtraction of Z -0.3 to Z -1.32 value.

38.209% - 9.342% =29.867%

The neaerest answer is A

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Find the area of each parallelogram plz help
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Answer:  The area of the parallelogram is:
_______________________________________________________
\frac{9393}{8}  in² = 1174 ⅛  in² = 1174.125 in² .
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
 A = base * height = b * h ;

From the figure (from the actual "question"):
_______________________________________
         b = 50.5 in.

         h = 23.25 in.
____________________________________________________________
Method 1)  A = b * h =
                 
                     =  (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as:  1174 <span>⅛ .
</span>____________________________________________________________
Method 2)  A = b * h =
             
                      =  (50 ½ in) * (23 <span>¼ in) =
   
                      =    (</span>\frac{101}{2} in) * (\frac{93}{4}<span> in) ;
</span>___________________________________________________________
Note:  "50 ½ " = [(50*2) + 1 ] / 2  = \frac{101}{2} ;

Note:  "23 ¼ " = [(23*4) + 1 ] / 4  = \frac{93}{4} ;
____________________________________________________________
→  A =  (\frac{101}{2} in) * (\frac{93}{4} in) ;
 
→  A = \frac{(101*93)}{(2*4)}  in² = \frac{9393}{8}  in² ; 
          
→  A = (9393/8) in² =  
         
→  A  = \frac{9393}{8}  in² = 1174 ⅛  in² = 1174.125 in² .
________________________________________________________
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