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3 years ago

Find the value of z. Round to the nearest hundredth. 30 and 14

Mathematics

1 answer:

Anna007 [38]3 years ago

6 0

I need more information for help you answer this

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Solve the following proportion for the unknown variable: 15/d = 24/40

Pavel [41]

Answer:
d = 25

Explanation:
To get the value of d, we will need to isolate the d on one side of the equation.

This can be done as follows:
 $\frac{15}{d} = \frac{24}{40}$ 

First, we will do cross multiplication as follows:
40*15 = 24*d
600 = 24d

Then, we will isolate the d as follows:
24d = 600
 $\frac{24d}{24} = \frac{600}{24}$

d = 25

Hope this helps :)

4 0

4 years ago

Read 2 more answers

For what value of x is sq 896z^15/225z^6 = xz^4/15

Ratling [72]

Answer:

Value of x is, 8

Step-by-step explanation:

Given: $\sqrt{\frac{896z^{15}}{225z^6}} =\frac{xz^4}{15} \sqrt{14z}$ ,.....[1]

To find the value of x:

Using exponent rules:

$(a^n)^m = a^{nm}$

$a^n \cdot a^m = a^{n+m}$

Taking square both sides in [1] we have;

$\frac{896z^{15}}{225z^6} = (\frac{xz^4}{15})^2 \cdot (14z)$

Simplify:

$\frac{896z^{15}}{225z^6} =\frac{x^2z^8}{225} \cdot (14z)$

$\frac{896z^{15}}{225z^6} =\frac{14x^2z^9}{225}$

Multiply both sides by $\frac{225}{14z^9}$ we get;

$x^2 = \frac{896 z^{15}}{225z^6} \times \frac{225}{14 z^9} = \frac{896 z^{15}}{14 z^{9+6}}$

Simplify:

$x^2 = \frac{896 z^{15}}{14 z^{15}} = 64$

$x = \sqrt{64}$

Simplify:

x = 8

Therefore, the value of x is, 8

5 0

3 years ago

What is the answer please tell me!

slava [35]

Answer:

add all of the absolute deviations and divide by the number of swimmers

Step-by-step explanation:

5 0

4 years ago

Drew ran 5 3/ 8 miles yesterday. Collin ran 8 5/12 miles yesterday. How much farther did Collin run? Choose the correct values t

Alex73 [517]

Drew = 5 3/8
Collin = 8 5/12

$\text {Difference = } 8\dfrac{5}{12} - 5\dfrac{3}{8} = 8\dfrac{10}{24} - 5\dfrac{15}{24} = 7\dfrac{34}{24} - 5\dfrac{15}{24} = 2\dfrac{19}{24}$

$\text {Answer : } 2\dfrac{19}{24}$

8 0

3 years ago

The answers to the problems

GuDViN [60]

Answer:

the fisrt question it b

4 0

3 years ago