Answer:
Over applied Overhead =$ 42,500
Explanation:
Actual Overhead $325,000
Estimated Overhead $350,000
Over applied overhead is when the Predetermined overhead is more than the actual overhead . Under applied overhead is when the Predetermined overhead is less than the actual overhead .
Predetermined Overhead rate= Overhead / total direct labor hours
= 350,000/ 500,000 (100)= 70%
Applied Overhead = Predetermined Overhead rate( actual direct labor hours)
= 70 % (525,000) = $367,500
Applied Overhead $367,500
Less Actual Overhead $325,000
Over applied Overhead =$ 42,500
Answer:
NPV =$ 60,311.80
Explanation:
<em>The net present value (NPV) of a project is the present value of cash inflow less the present value of cash outflow of the project.</em>
NPV = PV of cash inflow - PV of cash outflow
We can set out the cash flows of the project using the table below:
0 1 2 3
Operating cash flow 136,000 136,000 136,000
Initial cost (274,000)
Working capital (61,000 ) 61,000
Salvage value <u> </u> <u> </u> <u> </u> 1<u>5000 </u>
Net cashflow <u> (335,000) 136,000 136,000 212,000.</u>
PV inflow= (136000)× (1.1)^(-1) + (136,000× (1.1)^(-2) + (112,000)× (1.1)^(-3)
= 395,311.80
NPV =395,311.80 -335,000
=$ 60,311.80
Answer:
C, D , E , F.
Explanation:
These all are connected with money.
Sorry if I don't get this right I never had this question before.
Answer:
Incomplete question
First aspect of the question is typed below.
The shape of the distribution of the time required to get an oil change at a 20-minute oil-change facility
is unknown. However, records indicate that the mean time is 2l.2-minutes, and the standard deviation 3.5 minutes.
Explanation:
Employees bonus $50
35 oil changes between 10:00 am to 12:00pm
n = 35
10% changes
So, the z - score can be calculated using
z-score = InvNorm(0.10)
z-score = -1.28
So, given that,
Standard deviation is 3.5minutes
σ = 3.5 minutes
Mean time is 21.2 minutes
μx = 21.2 minutes
Then,
σx = σ / √n
σx = 3.5 / √35
σx = 0.5916 minutes
Then, Z score can be written as
Z = (x - μx) / σx
-1.28 = (x - 21.2) / 0.5916
Cross multiply
-1.28 × 0.5916 = x - 21.2
-0.7573 = x - 21.2
x = 21.2 - 0.7573
x = 20.443 minutes
There is a 10% chance of being at or below a mean oil-change time of 20.44 minutes
