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lys-0071 [83]
4 years ago
15

How would you do 0.793= n+0.65

Mathematics
2 answers:
dimulka [17.4K]4 years ago
7 0

Answer: 0.143

Step-by-step explanation: 0.793 - 0.65 = n

0.793-0.65=0.143

nlexa [21]4 years ago
5 0

Answer:

n=0.143

Step-by-step explanation:

by substracting 0.65 from both sides we get

n=0.793-0.65

ie)n=0.143

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2. Find the value of x in the triangle. Round your answer to the nearest tenth of a degree. Show your work.
yarga [219]

Answer:

\displaystyle 61,9° ≈ x

Step-by-step explanation:

We have to determine which trigonometric ratio to use, depending on what is displayed for us, and we will be using the <em>cotangent</em><em> </em>[or <em>tangent</em>] ratio, however, aside we are solving for an <em>angle</em><em> </em><em>measure</em>, we must use the inverse:

\displaystyle cot^{-1}\: \frac{8}{15} ≈ 61,92751306° ≈ 61,9° \\ \\ OR \\ \\ tan{-1}\: 1\frac{7}{8} ≈ 61,92751306° ≈ 61,9°

Extended Information on Trigonometric Ratios

\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ

I am joyous to assist you anytime.

3 0
3 years ago
193.87 divided by 5 estimate
dem82 [27]
Just use a calculator bro
5 0
3 years ago
Volume of a cylinder with a radius of 13 in and height of 30 in
Elodia [21]

Answer:

V≈15927.87 in³

Step-by-step explanation:

The volume of a cylinder is found by multiplying the area of its top or base by its height and is defined as: V = π*r²*· h

3 0
3 years ago
Read 2 more answers
can someone help me find the missing width in this geometry problem? 10th grade geometry, will reward brainly.
Nadya [2.5K]

Answer:

I think x is equal to 6. Correct me if I'm wrong!

4 0
2 years ago
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To mix plaster for a dental model, 35 mL of water is used for 100g of plaster. How many mL of water should be used for 250g of p
laila [671]

Okay, here we have this:

Considering the provided information, we are going to calculate the requested value, so we obtain the following rule of three:

\begin{gathered} \frac{x}{35mL\text{ of water}}=\frac{250g\text{ of plaster}}{100g\text{ of plaster}} \\ x=\frac{250g\text{ of plaster}}{100g\text{ of plaster}}\cdot35mL\text{ of water} \end{gathered}

Solving for x:

\begin{gathered} x=2.5\cdot35mL\text{ of water} \\ x=87.5mL\text{ of water} \end{gathered}

Finally we obtain that 87.5mL of water should be used for 250g of plaster.

3 0
1 year ago
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