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DochEvi [55]
3 years ago
6

How much mass of iodine would react with 48 grams of magnesium to make magnesium iodide?

Chemistry
1 answer:
kodGreya [7K]3 years ago
3 0

Answer:

Mass = 507.6 g

Explanation:

Given data:

Mass of Mg = 48 g

Mass of iodine react = ?

Solution:

Chemical equation:

Mg + I₂ → MgI₂

Now we will determine the number of moles of Mg.

Number of moles = mass/ molar mass

Number of moles = 48 g/ 24 g/mol

Number of moles = 2 mol

Now we will compare the moles of Mg with iodine.

                       Mg           :           I₂

                         1             :            1

                         2            :           2

Mass of iodine:

Mass = number of moles × molar mass

Mass = 2 mol × 253.8 g/mol

Mass = 507.6 g

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<h2>Hello!</h2>

The answer is:

The new temperature will be equal to 4 K.

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<h2>Why?</h2>

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Charles's Law establishes a relationship between the volume and the temperature at a gas while its pressure is constant.

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From Charle's Law, we have:

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From the question, we were told that:

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Now, we have 4 atoms of H on the right side and 1atom on the left side. It can be balance by putting 4 in front of HCl as shown below:

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