Question

How much mass of iodine would react with 48 grams of magnesium to make magnesium iodide?

Answer 1

Answer:

Mass = 507.6 g

Explanation:

Given data:

Mass of Mg = 48 g

Mass of iodine react = ?

Solution:

Chemical equation:

Mg + I₂ → MgI₂

Now we will determine the number of moles of Mg.

Number of moles = mass/ molar mass

Number of moles = 48 g/ 24 g/mol

Number of moles = 2 mol

Now we will compare the moles of Mg with iodine.

                       Mg           :           I₂

                         1             :            1

                         2            :           2

Mass of iodine:

Mass = number of moles × molar mass

Mass = 2 mol × 253.8 g/mol

Mass = 507.6 g