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OLEGan [10]
3 years ago
10

What is Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium

Chemistry
1 answer:
hram777 [196]3 years ago
3 0

The Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium concentrations are Keq = 1.5. The correct option is D.

<h3>What is Keq?</h3>

Keq is the ratio of the concentration of reactant to the concentration of the product.

The balanced equation is

N₂ + 3H₂  = 2NH₃

The equilibrium constant is \rm \dfrac{[NH_3]^2}{[N_2]\; [H_2]^3}

The given concentrations of the compounds have been:

Ammonia = 3 M

Nitrogen = 1 M

Hydrogen = 2 M

\rm \dfrac{9}{1\times 8} = 1.5

Thus, the correct option is D. Keq = 1.5.

Learn more about Keq

brainly.com/question/24059926

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Which carbon skeleton represents a ketone?
julsineya [31]

Yo sup??

The correct answer is option C

the rest are aldehyde, carboxylic acid and ether respectively.

Hope this helps.

5 0
3 years ago
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A Questic
Ivanshal [37]

Answer:

No, it is not feasible because the Gibbs free energy change is positive

Explanation:

∆Hreaction= (-602 KJ/mol) - (-348 KJ/mol) = -254 KJ/mol

∆Sreaction = (42 + 27) J/Kmol - (33 + 44) J/K = -8J/Kmol

From;

∆G = ∆H - T∆S

∆G = 254 × 10^3 J/mol - [340K × (-8 J/Kmol)]

∆G = 2.57 × 10^5 J/mol

Note that when the change in free energy is positive, a reaction is non spontaneous. Only a reaction that has a negative change in free energy is spontaneous.

3 0
3 years ago
If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is
mojhsa [17]

Answer:

MnO- Manganese Oxide

Explanation:

Empirical formula: This is the formula that shows the ratio of elements

present in a  

compound.

   

How to determine Empirical formula

1. First arrange the symbols of the elements present in the compound

alphabetically to  determine the real empirical formula. Although, there

are exceptions to this rule, E.g H2So4

2. Divide the percentage composition by the mass number.

3. Then divide through by the smallest number.

4. The resulting answer is the ratio attached to the elements present in

a compound.

           

                                                                              Mn                         O    

                         

% composition                                                      72.1                      27.9    

                       

Divide by mass number                                       54.94                     16  

                                 

                                                                               1.31                      1.74    

                       

Divide by the smallest number                         1.31                      1.31                          

                                                                               1                    1.3

                                                 

The resulting ratio is 1:1

 

Hence the Empirical formula is MnO, Manganese oxide

8 0
4 years ago
How many sig figs are in 1401.00
matrenka [14]

Answer:

6   We know it is closer to 1401.00 than 1400.99 or 1401.01 therefor the 6 sig figs

Explanation:

7 0
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Ground is used for agriculture, sink water, hose water, and even drinking water (from the aqueducts).
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