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OLEGan [10]
2 years ago
10

What is Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium

Chemistry
1 answer:
hram777 [196]2 years ago
3 0

The Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium concentrations are Keq = 1.5. The correct option is D.

<h3>What is Keq?</h3>

Keq is the ratio of the concentration of reactant to the concentration of the product.

The balanced equation is

N₂ + 3H₂  = 2NH₃

The equilibrium constant is \rm \dfrac{[NH_3]^2}{[N_2]\; [H_2]^3}

The given concentrations of the compounds have been:

Ammonia = 3 M

Nitrogen = 1 M

Hydrogen = 2 M

\rm \dfrac{9}{1\times 8} = 1.5

Thus, the correct option is D. Keq = 1.5.

Learn more about Keq

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N2 + 3 H2 --&gt; 2 NH3
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Answer:

4 moles of NH3 will be produced

Explanation:

The reaction expression is given as:

            N₂  +  3H₂  →  2NH₃

We have to check that the equation of the reaction is balanced.

 Then;

      if 2 mole of N₂ reacts;

 1 mole of N₂ will react with 3 mole of H₂ to produce 2 mole of NH₃

2 mole of N₂ will react with (2x3)mole of H₂ to produce (2x2)mole of NH₃

                                                    6mole of H₂ to produce      4 mole of NH₃

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A sample was prepared by mixing 18. ml of 3.00 x 10^-3 m crystal violet (cv) with 2.00 ml of 0.250 m naoh. calculate the resulti
Aleks [24]

Answer : The resulting concentrations of CV and NaOH are 0.0027 M and 0.025 M respectively.

Explanation :

Step 1 : Find moles of crystal violet and NaOH.

The molarity formula is

Molarity = \frac{mol}{L}

Molarity of crystal violet = 3.00 \times 10^{-3} = \frac{mol (CrystalViolet)}{L}

The volume of crystal violet solution is 18 mL which is 0.018 L.

Moles of crystal violet = 3.00 \times 10^{-3} \times 0.018 = 5.4 \times 10^{-5}

Moles of crystal violet = 5.4 x 10⁻⁵

Moles of NaOH = Molarity \times L = 0.250 \times 0.00200 = 5.00 \times 10^{-4}

Moles of NaOH = 5.00 x 10⁻⁴

Step 2 : Find total volume of the solution

The total volume of the solution after mixing NaOH and crystal violet is

0.018 L + 0.00200 = 0.020 L

Step 3 : Use molarity formula to find final concentrations

Molarity of crystal violet = \frac{mol(CrystalViolet)}{Total Volume(L) } = \frac{5.4 \times 10^{-5}}{0.020} = 2.7 \times 10^{-3}

Final concentration of CV = 0.0027 M

Molarity of NaOH= \frac{mol(NaOH)}{Total Volume(L) } = \frac{5.00 \times 10^{-4}}{0.020} = 0.025 \times 10^{-3}

NaOH is a strong base and dissociates completely as follows.

NaOH (aq) \rightarrow Na^{+} (aq) + OH^{-} (aq)

The mole ratio of NaOH and OH⁻ is 1:1 . Therefore the concentration of OH⁻ is same as that of NaOH.

Concentration of OH⁻ = 0.025 M

8 0
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