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DENIUS [597]
3 years ago
12

Consider the change given below. At constant pressure, is work done by the system on the surroundings? By the surroundings on th

e system? Or is no work done? Hg(l) → Hg(g)
Chemistry
1 answer:
alexira [117]3 years ago
7 0

Answer : At constant pressure work is done by the system on the surroundings.

Explanation :

Work done : Any quantity that flows across the boundary of a system during a change in its state and it completely convertible into the lifting of a weight in the surroundings.

Formula for work done is:

w=-p_{ext}dV

Sign convention :

  • When volume expand then system work that means work done by the system.

w = (-ve)

  • When volume compress then surrounding work that means work done on the system.

w = (+ve)

The given reaction is:

Hg(l)\rightarrow Hg(g)

This is a evaporation process in which phase changes from liquid state to gaseous state at constant temperature.

At constant pressure, work depends only on volume.

In evaporation process, the volume expand that means work is done by the system on the surroundings.

Sign convention is, w = (-ve)

Thus, at constant pressure work is done by the system on the surroundings.

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1.386 g of Mg ribbon combusts to form 2.309 g of oxide product. The mass percent of oxygen in the oxide is 40.0 %.

Let's consider the reaction for the combustion of Mg.

Mg + 1/2 O₂ ⇒ MgO

1.386 g of Mg combusts to form 2.309 g of MgO. We want to determine the mass of oxygen in MgO. According to Lavoisier's law of conservation of mass, matter is not created nor destroyed over the course of a chemical reaction. Then, the mass of Mg in the reactants is equal to the mass of Mg in MgO. The mass of the magnesium oxide is the sum of the masses of magnesium and oxygen. The <u>mass of oxygen in the oxide</u> is:

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We can calculate the mass percent of O in MgO using the following expression.

\% O = \frac{mO}{mMgO} \times 100\% = \frac{0.923 g}{2.309g} \times 100\%  = 40.0 \%

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Can you store cuso4 in an aluminum container? explain your reasoning
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We can store the copper sulphate solution in alumiun container, if cover on alumiun is present.

<h3>Can you store cuso4 in an aluminum container?</h3>

Aluminium is more reactive than copper so the Aluminium will displace copper sulphate from its solution by reacting with it but if there is cover on the aluminium then the alumium can't react with copper.

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Answer:

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The number of molecules = 0.038 X 6.022x10^23 = 2.29x10^23

the number of positive ions present in the ammonium sulphate solution:

2 positive ions for every 1 molecule of (NH₄)₂SO₄

so 2 x 2.29x10^23 = 4.58x10^23

the number of negative ions present in the ammonium sulphate solution

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