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kirill [66]
3 years ago
5

2 and 1 fourth divided by 3 and 1 fifth simplified

Mathematics
1 answer:
yaroslaw [1]3 years ago
7 0

Answer:52

Step-by-step explanation:

So let’s take the base as ‘x’

X+28=180(sum of lengths of triangle is always 180)

X=180-28

X=52

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Here it is given that AB || CD

< EIA = <GJB

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∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

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m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

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∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

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