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kirill [66]
3 years ago
5

2 and 1 fourth divided by 3 and 1 fifth simplified

Mathematics
1 answer:
yaroslaw [1]3 years ago
7 0

Answer:52

Step-by-step explanation:

So let’s take the base as ‘x’

X+28=180(sum of lengths of triangle is always 180)

X=180-28

X=52

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An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
"at the end of the year Juan has $52.71 more than 4 times his balance at the beginning of the year if his ending balance was $17
Salsk061 [2.6K]
At the end of the year, Juan has 52.71 more than 4 times his balance at the beginning. Okay, let's set this up.

4x + 52.71
(4 times) (52.71 more)
His ending was 172.90, so
4x + 52.71=172.90
4x= 120.19
x= 30.05
He had $30.05 at the beginning of the year.
8 0
4 years ago
A car travels at an average speed of 40 miles per hour for the first 100 miles of a 200-mile trip, and at an average speed of 50
Harlamova29_29 [7]
Total distance = 200 miles

Time needed for the first 100 miles
= 100 ÷ 40 = 2.5 hours

Time needed for the second 100 miles
= 100 ÷ 50 = 2 hours

Total time = 2.5 + 2 = 4.5 hours

Average speed = 200 ÷ 4.5 hours = 44.4 miles per hour
3 0
3 years ago
Using the letters in the word INNOVATIVE, find the number of permutations that can be formed using 4 letters at a time. Show you
lyudmila [28]

Answer:  1) 5040 and 2) 165

Step-by-step explanation:

1) Here total number of letters = 10

The number of permutations that can be formed using 4 letters at a time

= P (10, 4)

= 10_P_4

= \frac{10!}{(10-4)!}

=  \frac{10!}{6!}

= \frac{10\times 9\times 8\times 7\times 6!}{6!}

= 10 × 9 × 8 × 7

= 5040

2) Here the total number of machine = 11

The different combinations of machines can Geoff choose from to use

= 11_C_3

= \frac{11!}{(11-3)!3!}

= \frac{11!}{8!3!}

= \frac{11\times 10\times 9\times 8!}{8!\times 6}

= 11 × 5 × 3

= 165

5 0
3 years ago
Heather, a sociology major is interested in studying mass media topics. She is particularly interested in the percentage of mass
Mrrafil [7]

Answer:

Pvalue

Step-by-step explanation:

The Pvalue measure which takes up a value in the range 0 - 1 is a statistical measure used on hypothesis testing to measure the likelihood of obtaining result atleast as extreme as the outcome of the statistical hypothesis test, The Pvalue is used in hypothesis testing to make a case for the alternative hypothesis, which involves being compared with the α - value.

Lower p values favors the adoption of alternative depending on how extreme th α-value is. The Pvalue is dependent on the value if the test statistic.

6 0
3 years ago
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