Answer:
C = (36/3)* $24
C = $288
Step-by-step explanation:
In this question, we are asked to write an equation for cost c of the section of fence needed for the garden and the solve for the value c.
C is already assigned as the cost of the sections she needs for her garden.
We were made to understand that the perimeter of the garden is 36 feet, with a 3 feet each section. Now, what we need to do is to know the number of sections that we have. Since, each section is 3 feet, and the total perimeter is 36 feet, this means that the total number of sections needed would be 36/3. Each of the section as we were told costs $24, so we can then proceed to calculate the value of C from there.
C = (36/3)* $24
This is the equation that gives the cost. The actual value of the cost is thus:
C = 12 * 24 = $288
The total cost of the sections if the Fence is $288
The length of the wire is the length of the hypotenuse of a triangle with one leg 60 inches and the other leg 8*4 in = 32 inches.
√(60² +32²) = √4624 = 68
The wire is 68 inches long.
_____
Consider what happens if you wrap a paper triangle of those dimensions around the pipe. The hypotenuse edge traces the path of the wire.
Answer:
Store #1
Step-by-step explanation:
The expression (-2 - 6i)-(-2-4i) to a + bi form is 0 - 2i.
Complete question.
Simplify the expression to a + bi form:
(-2 - 6i)-(-2-4i)
Square root of any negative number are expressed as a complex number. For example i = √-1
Complex numbers are generally written in the format z = x+iy
Given the expression (-2 - 6i)-(-2-4i)), in expansion:
(-2 - 6i)-(-2-4i)
= -2 - 6i + 2+4i
Collect the like terms
= (-2 + 2) - 6i + 4i
= 0 - 2i
Therefore the expression (-2 - 6i)-(-2-4i) to a + bi form is 0 - 2i.
Learn more on complex number here: brainly.com/question/12375854
Answer:
The correct answer is - 1/2 or 50% for first and second child to be affected.
Step-by-step explanation:
Achondroplasia is an autosomal dominant disorder. Autosomal dominant disorder refers to the presence of a single copy of the defective gene that is enough to lead to dwarfness.
A cross of achondroplasia (Aa) parent to a person of normal height (aa) result in half of their children will be affected with dwarfism and the other half will be normal.
a cross between affected or dwarf and normal parent
Aa X aa
Punnett square:
a a
A Aa Aa
a aa aa
Aa- dwarfness
aa- normal height
The probability that both their first child and second child would have achondroplasia is
2/4 =1/2 or 50%.
