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Alex
3 years ago
13

Olivia is making lunch. She uses 1 3/8 pounds of carrots in soup. She uses 4/5 pound of carrots in a salad. About how many pound

s of carrots did Olivia use in all?
Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

2 7/40 Carrots

About 2 Carrots

1 3/8+4/5 = 1 15/40+32/40 = 1 47/40 = 2 7/40

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The number of sit-ups that all tenth-grade girls can do in 5 minutes is normally distributed. beth surveyed 20 of her fellow int
Luda [366]

The true statement is as follows "No because she did not use a simple random sample".

<h3>What is random sampling?</h3>

Random sampling is the method to choose the given samples of observation to make assumptions about the population.

It is given that

Population: All tenth-grade girls

Sample: 20 intramural tennis players

The 20 intramural tennis players cannot represent all tenth-grade girls.

This is so because the selection is biased here, and it could not be used to make inferences about the overall population. then she did not use a simple random sample.

Hence, the true statement is (b)

Read more about random sampling at:

brainly.com/question/1334729

5 0
2 years ago
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5√-54 in simplest radical form
olga nikolaevna [1]

The answer is 15i radical 6

3 0
3 years ago
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ABCD is a trapezium.
lisabon 2012 [21]

The length of BC is 4.674 m

<u>Explanation:</u>

Given:

Angle A = angle B = 90°

AD = 2.1 m

AB = 1.9 m

CD= 3.2 m

An image is inserted for the reference

According to the figure,

a is the base

b is the height

c is the hypotenuse

Using pythagoras theorm:

a² + b² = c²

a² + (1.9)² = (3.2)²

a² + 3.61 = 10.24

a² = 6.63

a = 2.574

BC = 2.1 + 2.574

BC = 4.674m

Therefore, the length of BC is 4.674 m

7 0
3 years ago
In a triangle, two sides that measure 8 centimeters and 11 centimeters form an angle that measures 82°. to the nearest tenth of
Gwar [14]
We can use the Сosine formula to solve this problem.
<span>First we must find the third side (АС) of the triangle:
</span>
AC^2=AB^2+BC^2-2*AB*BC*cos82^o \\ AC^2=8^2+11^2-2*8*11*0.1392 \\ AC^2=64+121-24.4992= 160.508 \\ AC= \sqrt{160.508} \approx  12.67 \ cm
<span>
The smallest angle of the triangle lies opposite the smallest side, so we need to find m</span>∠C.

cosC= \frac{AC^2+BC^2-AB^2}{2*AC*BC}  \\  \\ cosC= \frac{12.67^2+11^2-8^2}{2*12.67*11}= \frac{160.53+121-64}{278.74} = \frac{217.53}{278.74} \approx  0.7804

Now we can use Bradis's Table (I don't know the name in English, maybe Trigonometric Table?) to find m∠C:

m∠С = 38°42' = 38.7°

Answer: 38.7°


<span>I hope this helps</span>

7 0
3 years ago
Please help i need now
Sunny_sXe [5.5K]

Answer:

8x10^-12

Step-by-step explanation:

Hope that helps.

7 0
2 years ago
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