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Alexus [3.1K]
3 years ago
5

Arrange the decimals from 1. greatest to least

Mathematics
1 answer:
Iteru [2.4K]3 years ago
3 0

Answer:

hi I am new to brainly want to be my friend

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What is the standard form for 8 hundreds plus 2 hundreds
Gennadij [26K]

Answer:

800+200

Step-by-step explanation:

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trey is selling candy bars to raise money for his basketball team. the team receives $1.25 for each candy . he has already sold
zlopas [31]

Answer:

He has earned $31.25 for his basketball team.

Step-by-step explanation:

25 * 1.25 = 31.25

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3 years ago
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Please help me in this question.Tell me if it is good. And if it is not good then do it for me please.
Orlov [11]

Answer:

Y = 170, Z = 64.

Step-by-step explanation:

Since y is the external angle to x, which you got right, it is in fact, 180-10, = 170 degrees. And since z is the external to our unknown angle, that means it is equal to the sum of the other two angles in the triangle. That means z is 54 + 10, which is 64.

6 0
3 years ago
Are 0,2,5 closed or not under addition
kvasek [131]

Answer:

There are closed addition.

Step-by-step explanation:

Closure (mathematics) ... For example, the positive integers are closed under addition, but not under subtraction: is not a positive integer even though both 1 and 2 are positive integers. Another example is the set containing only zero, which is closed under addition, subtraction and multiplication.

So, 0,2,5 are closed addition

Please mark me brainliest.

3 0
3 years ago
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
3 years ago
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