First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
The results in the question conclude that it is an isosceles triangle so your answer can vary; for example, your could be 10, 22, 18 which would make the perimeter 50 like the question states. So your answer will vary anyways you just have to remember that it is an isosceles triangle so all three sides will be a different length.
Answer: the converse
Why: “if Q then P”, if 44 then acute
X-10>15.........................................
Answer:
7x² + 5x
Dtep-by-step explanation:
(9x² + 8x) - (2x² + 3x)
9x² + 8x - 2x²- 3x
7x² + 5x
