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2 years ago

Line AB contains points A (−6, 3) and B (2, −5). Line AB has a slope that is

2 answers:

Alex2 years ago

7 0

Slope (m) = y2-y1 / x2-x1
m = 3+5 / -6-2
m = 8/-8
m = -1

In short, Your Answer would be Option D) Negative

Hope this helps!

ss7ja [257]2 years ago

5 0

To find the slope you must find the gradient i think so
gradient formula is change in y /change in x
sooo
=3--5/-6-2
=8/-8
=-1
so it is negative

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SCCoast, an Internet provider in the Southeast, developed the following frequency distribution on the age of Internet users. Fin

Tomtit [17]

Answer:

Mean: 40.17 years.

Standard deviation: 10.97 years.

Step-by-step explanation:

The frequency distribution is in the attached image.

We can calculate the mean adding the multiplication of midpoints of each class and frequency, and dividing by the sample size.

The midpoints of a class is calculated as the average of the bounds of the class.

Then, the mean can be written as:

$E(X)=\dfrac{1}{N}\sum f_iX_i\\\\\\E(X)=\dfrac{1}{60}(3\cdot15+7\cdot25+18\cdot35+20\cdot45+12\cdot 55)=\dfrac{45+175+630+900+660}{60}\\\\\\E(X)=\dfrac{2,410}{60}=40.17$

The standard deviation can be calculated as:

$s=\sqrt{\dfrac{1}{N-1}\sum f_i(X_i-E(X))^2}\\\\\\s=\sqrt{\dfrac{1}{59}[3(15-40.17)^2+7(25-40.17)^2+18(35-40.17)^2+20(45-40.17)^2+12(55-40.17)^2]}$

$\\\\\\s=\sqrt{\dfrac{1}{59}( 1,900.59 + 1,610.90 + 481.12 + 466.58 + 2,639.15 )}\\\\\\s=\sqrt{\dfrac{ 7,098.33 }{59}}=\sqrt{120}=10.97$

4 0

3 years ago

Which of the following constants can be added to x2 - 3x to form a perfect square trinomail?

serious [3.7K]

The constant that can be added to $x^2$ - 3x to form a perfect square trinomial is $2\frac{1}{4}$

The given expression is

$x^2$ - 3x

To form a perfect square trinomial

$(a-b)^2 =a^2-2ab+b^2$

The given expression is

$x^2$ - 3x

first we have to add a constant term with it

$x^2$ - 3x + z

By comparing the given expression and the perfect square trinomial

$a^2 =x^2$

a = x

Similarly

-2ab = 3x

where know a =x

Then,

-2b = 3

b = -3/2

Similarly

$b^2 = z$

$(\frac{-3}{2})^2$ = z

9/4 = z

Convert the simple fraction to mixed fraction

9/4 = $2\frac{1}{4}$

Hence, the constant that can be added to $x^2$ - 3x to form a perfect square trinomial is $2\frac{1}{4}$

The complete question is :

Which of the following constants can be added to x2 - 3x to form a perfect square trinomial?

$1\frac{1}{2},2\frac{1}{4}$ and $4\frac{1}{2}$

Learn more about perfect square trinomial here

brainly.com/question/16615974

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4 0

8 months ago

How to factor 2n^2+3n-9 without splitting the middle term

kozerog [31]

$2n^2+3n-9= \\\\ a=2 \\ b=3 \\ c=-9 \\\\ \Delta= 3^2-4*2*(-9)=9+72\to\boxed{81} \\\\ x_1;x_2=\frac{-3 +\-\sqrt{81}}{2*2}= \frac{-3+/- 9}{4} \\\\ x_1=\frac{-3+9}{4}=\frac{6}{4}\to\boxed{\frac{3}{2}} \\\\ x_2=\frac{-3-9}{4}=\frac{-12}{4}\to\boxed{-4} \\\\ 2n^2+3n-9=(x-\frac{3}{2})(\x+4)$