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Answer:
The 90% confidence interval for the population mean iron concentration is between 0.167 cc/m³ and 0.195 cc/m³.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 0.181 - 0.0140 = 0.167 cc/m³.
The upper end of the interval is the sample mean added to M. So it is 0.181 + 0.0140 = 0.195 cc/m³.
The 90% confidence interval for the population mean iron concentration is between 0.167 cc/m³ and 0.195 cc/m³.
So attached is a picture of the triangle you are talking about and listed under are the choices:
A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
<span>D.) Tan Z=a/b
</span>
The answer would then be B. SinX = c/b.
Just remember SOH CAH TOA:
Sinθ= Opposite Cosθ = Adjacent Tanθ= Opposite
Hypotenuse Hypotenuse Adjacent
Using the triangle in the scenario, you just need to identify which side is which.
Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c
SinZ= a CosZ = b TanZ= a
c c b
Given m∠X:
Adjacent = b
Opposite = a
Hypotenuse = c
SinX= <u> b </u> CosX =<span><u> a </u></span> TanX=<span><u> b </u></span>
c c a
So the answer is B.
Attached is a picture of how I assigned the sides depending on the angle used.
A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
<span>D.) Tan Z=a/b
</span>
The answer would then be B. SinX = c/b.
Just remember SOH CAH TOA:
Sinθ= Opposite Cosθ = Adjacent Tanθ= Opposite
Hypotenuse Hypotenuse Adjacent
Using the triangle in the scenario, you just need to identify which side is which.
Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c
SinZ= a CosZ = b TanZ= a
c c b
Given m∠X:
Adjacent = b
Opposite = a
Hypotenuse = c
SinX= <u> b </u> CosX =<span><u> a </u></span> TanX=<span><u> b </u></span>
c c a
So the answer is B.
Attached is a picture of how I assigned the sides depending on the angle used.