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s2008m [1.1K]
3 years ago
9

See the file below to see my question :)

Mathematics
1 answer:
RideAnS [48]3 years ago
3 0

9514 1404 393

Answer:

  • a = 3
  • b = -18

Step-by-step explanation:

Using the least common denominator, we have ...

  2-\dfrac{x+1}{x-2}-\dfrac{x-4}{x+2}\\\\=\dfrac{2(x-2)(x+2)-(x+1)(x+2)-(x-4)(x-2)}{(x-2)(x+2)}\\\\=\dfrac{2(x^2-4)-(x^2+3x+2)-(x^2-6x+8)}{x^2-4}\\\\=\dfrac{(2-1-1)x^2+(-3+6)x+(-8-2-8)}{x^2-4}=\boxed{\dfrac{3x-18}{x^2-4}}

The values of a and b are ...

  a = 3

  b = -18

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IRISSAK [1]

Answer:

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6 0
3 years ago
(4x^3y)(-2x^4y^-1)^2(6x^8y^5)^0 PLSSSSSSSSSSSSSSSSS HELP ME !!!!!!!!!
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Answer:

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Step-by-step explanation:

5 0
2 years ago
A linear function is written:<br> f(x) = 3/2x-4<br> What is the value of f(5)?
valentinak56 [21]

Answer:

f(5)=3.5

Step-by-step explanation:

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Hope this helped!! Have an amazing day :D

4 0
3 years ago
Two more than the product of a number and 6 is 8
solniwko [45]

Answer: 6n + 2 = 8

Step-by-step explanation:

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4 0
3 years ago
Shown here are four frequency distributions. Each is incorrectly constructed. State the reason why.
Tanya [424]

Answer/Step-by-step explanation:

a. The the class width for the 1st, 2nd, 3rd, and 5th row equal 5 in the frequency distribution. Whereas, in the 4th row, the class width is 4 (49 - 45). This makes the construction incorrect.

b. Here, the upper limit of each consecutive class was used as the lower limit if the next class. For example, 9 is a member of the first class, which is the upper limit if the class in the first row, it ought not to be included as a member of the next class in the second row.

c. In the 3rd row, the lower limit of the class should be 133, NOT 138.

d. Different class width were used.

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Row 3 class width = 25 - 20 = 5

Row 4 class width = 28 - 26 = 2

Row 5 class width = 32 - 29 = 3

8 0
3 years ago
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