Answer:
Step-by-step explanation:
Check attachment for solution
So, I believed the first case is correct since it gave us one of the option, then, the answer is D.
9√3.
So, UW = 9√3
Answer:
The probability that a watermelon will weigh between 6.8 lbs and 9.3 lbs.
P(6.8 ≤X≤9.3) = 0.5932
Step-by-step explanation:
Step 1:-
by using normal distribution find the areas of given x₁ and x₂
Given The average watermelon weighs 8 lbs
μ = 8
standard deviation σ = 1.5
I) when x₁ = 6.8lbs and μ = 8 and σ = 1.5

ii) when x₂ = 9.3 lbs and μ = 8 and σ = 1.5

<u>Step2</u>:-
The probability that a watermelon will weigh between 6.8 lbs and 9.3 lbs.
P(6.8 ≤X≤9.3) = A(z₂) - A(-z₁)
= A(0.866) - A(-0.8)
= A(0.866)+ A(0.8)
check below normal table
= 0.3051 + 0.2881
= 0.5932
<u>Conclusion</u>:-
The probability that a watermelon will weigh between 6.8 lbs and 9.3 lbs.
P(6.8 ≤X≤9.3) = 0.5932
Answer:
848.23
Step-by-step explanation:
Step 1: Find Volume Of The The Cake
Volume = 
Evaluate: ~848.23
Step 2: Find The Part The Was Eaten:
Full Circle: 360
Eaten = 25
Part: 25/360 = 14.4
Set 3: Find Volume Eaten:
14.4/848.23 = 58.90
Answer:
yes 6 is great answr\er
Step-by-step explanation: