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3 years ago

Assume that lines that appear to be tangents are tangents. O is the center of the circle.

Mathematics

1 answer:

scoray [572]3 years ago

8 0

Answer: the value of x is 45

Step-by-step explanation: its a little bit bigger than the 40 on the right

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I will give branlyest

Anon25 [30]

Answer:

15 3 over 100

$2 \frac{1}{2} + 4 \frac{1}{4} + 9 \frac{1}{4} = 15 \frac{3}{10}$

5 0

3 years ago

22 POINTS, NEED URGENT HELP

rjkz [21]

1) start with (x-h)^2 + (y-k)^2 = r^2. Insert the given info: center at (-1,8) and radius 5:

(x+1)^2 + (y-8)^2 = 5^2 (answer)

7 0

3 years ago

$270 are shared in the ratio 4:5. what is the greater share?

jarptica [38.1K]

Answer:

$150

Step-by-step explanation:

5/(4+5) * 270 = 150

5 0

3 years ago

Por que la estadística es una ciencia ???<br><br>

Volgvan

I would say that statistics is a mathematical subject that allows you to explain scientific data. In a similar fashion, you could use mathematics to explain the various idea in physics as you can use statistics to interpret the results of experiments and the data collected.

Hope that helped!

3 0

2 years ago

For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean

ki77a [65]

Answer:

$P(Z>3) = 1-P(Z$

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu=?,\sigma=?)$

We are interested on this probability

$P(X>X+3\mu)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

And we can find the following probablity:

$P(Z>3) = 1-P(Z$

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a/2.0

3 0

3 years ago