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spayn [35]
3 years ago
11

A person buys X meter for 5

Mathematics
1 answer:
Nady [450]3 years ago
8 0

Step-by-step explanation:

I guess, it means every meter costs these amounts.

and the specified costs are not fit the whole bundle.

it is also unclear, if "half of it" means half of the original x meters, or half of the remaining meters (after selling 2/5 of the original meters). I assume the first.

so, we have

-5x

+ 2/5x × 5.5

+ 1/2x × 6.4

+ (10/10 - 4/10 - 5/10)x × 6 = + 1/10x × 6

= 120 ( a income minus costs is the profit, so balancing both sides in a "+" and "-" expression gives us the remaining profit).

about the line with the 1/10 :

the leftovers. 10/10 is the whole x at the beginning.

2/5 = 4/10.

1/2 = 5/10.

I brought all involved fractions to the same denominator of the smallest common multiple of 2 and 5 (10).

in full

-5x + (2/5)x×5.5 + (1/2)x×6.4 + (1/10)x×6 = 120

-5x + 2.2x + 3.2x + 0.6x = 120

-5x + 6x = 120

x = 120

so, he bought 120m in the first place.

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The probability that a single radar station will detect an enemy plane is 0.65.
taurus [48]

Answer:

a) We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

b) If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

Step-by-step explanation:

For each station, there are two two possible outcomes. Either they detected the enemy plane, or they do not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

The probability that a single radar station will detect an enemy plane is 0.65. This means that n = 0.65.

(a) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station?

This is the value of n for which P(X = 0) \leq 0.02.

n = 1.

P(X = 0) = C_{1,0}.(0.65)^{0}.(0.35)^{1} = 0.35

n = 2

P(X = 0) = C_{2,0}.(0.65)^{0}.(0.35)^{2} = 0.1225

n = 3

P(X = 0) = C_{3,0}.(0.65)^{0}.(0.35)^{3} = 0.0429

n = 4

P(X = 0) = C_{4,0}.(0.65)^{0}.(0.35)^{4} = 0.015

We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

(b) If seven stations are in use, what is the expected number of stations that will detect an enemy plane?

The expected number of sucesses of a binomial variable is given by:

E(x) = np

So when n = 7

E(x) = 7*(0.65) = 4.55

If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

6 0
3 years ago
solve the following system of equation using the substitution method y equals 3x - 14 y equals x - 10​
monitta

Answer:

(2,-8)

Step-by-step explanation:

y have

y=3x-14

y=x-10

we can substitute y in the first equation with x-10

x-10=3x-14

solve for x

4=2x

x=2

Now that we know what x equals we can solve for y

3(2)-14

6-14

-8=y

(2,-8)

7 0
3 years ago
74.141 rounded too the nearest tenth
Talja [164]

Answer:

74.1

Good Luck!!!

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