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xxMikexx [17]
3 years ago
13

Simplify the expression. Use the variables, numbers, and symbols that are shown. Drag them to the appropriate box in the polynom

ial. Use standard polynomial format.
x(2x + 3) + (x - 3)(x - 4)
Mathematics
2 answers:
Naya [18.7K]3 years ago
7 0

Answer:

3x^{2}-4x+12

Step-by-step explanation:

In this case we have to simplify the expression by giving it in the standard polynomial format, first we have to see what is the polynomial standard format, this is:

ax^{2} +bx+c

In the case of the expression presented we have to make the multiplications and additions to then organize the expression:

x(2x+3)+(x+3)(x+4)

First the multiplications:

2x^{2} +3x+x^{2} -4x-3x+12

Now the additions and organization:

3x^{2}-4x+12

Now we have the expression in the polynomial format.

Mice21 [21]3 years ago
4 0
3x^2-4x+12! Hope this helps.
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Answer:

Step-by-step explanation:

Remember:\\(a+b)(a-b)=a^2-b^2\\\\(6+5i)(6-5i)=6^2-(5i)^2=36-(-1)*25=36+25=61\\

8 0
3 years ago
A graph of x^2 + y^2 = 9 is shown on the grid. By drawing the line x + y = 2, solve the equations x^2 +y^2 =9. x + y = 2
Hatshy [7]

Answer:

Step-by-step explanation:

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5 0
3 years ago
Solve the system by using elementary row operations on the equations. Follow the systematic elimination procedure
Umnica [9.8K]

Answer:

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equations are  x₁+4 x₂ = 11 ...(i)

                                 2 x₁ + 7 x₂= 18 ...(ii)

The matrix form

                                A X = B

            \left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]

<u>Step(ii):-</u>

      \left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]

The Augmented Matrix form is

[AB] = \left[\begin{array}{ccc}1&4&11\\2&7&18\\\end{array}\right]

Apply Row operations,  R₂ → R₂-2 R₁

[AB] = \left[\begin{array}{ccc}1&4&11\\0&-1&-4\\\end{array}\right]  

The matrix form

                   \left[\begin{array}{ccc}1&4\\0&-1\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\-4\\\end{array}\right]

The equations are

                     x₁ + 4 x₂ = 11 ...(a)

                         - x ₂ = - 4

                            x ₂ = 4

Substitute   x ₂ = 4 in equation (a)

                      x₁ + 4 x₂ = 11

                      x₁ = 11 - 16

                        x₁ = -5

<u>Final answer</u>:-

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

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Answer:

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Step-by-step explanation:

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