Answer:
The interquartile range is the difference between the highest and lowest values in the middle of a data set.
Step-by-step explanation:
The range is the difference between the maximum and minimum value, hence, it cannot be greater than the maximum value, which is the greatest value in a dataset, the highest value a range could have being equal to the maximum value when the minimum vlaue of the dataset is equal to 0.
The mean is the average value of a dataset, hence, it cannot be greater than the maximum value.
The interquartile range is the middle 50% or half of a dataset and not the difference between the highest and lowest middle values in the middle. It is obtained by taking the difference of the upper and lower QUARTILE.
Answer:
in what time will 24000 amount to rs.30000 at 10% p.a?
Turn the percentage into a decimal.
6% = 0.06
Multiply.
990 * 0.06 = $54.9 (sales tax)
Add.
990 + 54.9 = $1,049.40 (total price)
Best of Luck!
Answer:
Step-by-step explanation:
<u>Ratios
</u>
We are given the following relations:
![a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]](https://tex.z-dn.net/?f=a%3D%5Csqrt%7B7%7D%2B%5Csqrt%7Bc%7D%5Cqquad%20%5Cqquad%5B1%5D)
![b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B63%7D%2B%5Csqrt%7Bd%7D%5Cqquad%20%5Cqquad%5B2%5D)
![\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bc%7D%7Bd%7D%3D%5Cfrac%7B1%7D%7B9%7D%20%5Cqquad%20%5Cqquad%20%5B3%5D)
From [3]:
Replacing into [2]:
We can express 63=9*7:
Taking the square root of 9:
Factoring:
Find the ration a:b:
Simplifying:
