Answer:
PR5T represents <em>6754.</em>
P = 6
R = 7
T = 4
Y = 5
Step-by-step explanation:
Let us try to understand the subtraction starting from the unit's digit.
P R 5 T
- 4 7 Y 6
-----------------
1 9 9 8
To get 8, 6 should be subtracted from 14
14 - 6 = 8
So, T should be equal unit digit of 14 <em>i.e.</em> T = 4 and 1 should be carried over from the ten's digit of PR5T.
Now, let us move to ten's digit:
P R 5 4
- 4 7 Y 6
-----------------
1 9 9 8
To get 9, 6 should be subtracted from 15. But 1 is already carried to unit's place So, we have actually 14 here
14 - Y = 9
So, Y = 5
Moving to hundred's place:
R - carry - 7 = 9
Carry is 1, so R = unit's place of 9 + 8 i.e. R = 7
Moving to thousand's place:
P - carry - 4 = 1
Here carry is 1
So, P = 1 + 4 + 1 = 6
So, the number PR5T is <em>6754.</em>
Answer:
In the first one you are missing (x - 3) so it will be 4(x - 3) and if you factor it out it will be 4x - 12
In the second one you are missing a (x -5)which means 9x(x -5) or when you factor it out it will be 9x^2 - 45x
Step-by-step explanation:
3x^2 -23x + 40 = (3x - 8) (x - 5)
3x^2 -17x + 24 = (3x -8) ( x - 3)
Answer:
Step-by-step explanation:
Anything that is multiplied greater than 1 will be greater than what the other factor is. You are correct!
Answer:
![67.5\text{ [square units]}](https://tex.z-dn.net/?f=67.5%5Ctext%7B%20%5Bsquare%20units%5D%7D)
Step-by-step explanation:
The composite figure consists of one rectangle and two triangles. We can add up the area of these individual shapes to find the total area of the irregular figure.
<u>Formulas</u>:
- Area of rectangle with base
and height 
: 
- Area of triangle with base and height :
By definition, the base and height must intersect at a 90 degree angle.
The rectangle has a base of 10 and a height of 5. Therefore, its area is 
.
The smaller triangle to the left of the rectangle has a base of 2 and a height of 5. Therefore, its area is 
.
Finally, the larger triangle on top of the rectangle has a base of 5 and a height of 5. Therefore, its area is 
.
Thus, the area of the total irregular figure is:
![50+5+12.5=\boxed{67.5\text{ [square units]}}](https://tex.z-dn.net/?f=50%2B5%2B12.5%3D%5Cboxed%7B67.5%5Ctext%7B%20%5Bsquare%20units%5D%7D%7D)
