1. independent, unless the coins are different
2. independent
3. independent
4. not independent
If something is independent that means it doesn't effect the the other result. for example: Question one is independent because taking one coin doesn't effect the likelyhood of selecting another coin (if they're the same type of coin)
Answer:
0.783
Step-by-step explanation:
To find first r and then r square for the data
correlation coefficient of x and y = Cov (x,y)/std dev x * std dev Y
Cov (x,y) = E(xy) -E(x)E(y)
Hence calculations would be as follows:
x y xy
1 2 2
2 10 20
5 5 25
7 18 126
10 25 250
Mean 5 12 84.6
Cov E(xy)-E(x)E(y) 24.6
r 0.884640297
r^2 0.782588454
so answre is 0.783 after rounding off.
Bread - 3 choices
Meat - 5 choices
Veggies - 7 choices
1br 1mt 1vg = 3×5×7 = 105
1br 2mt 3 vg = 3×5×4×7×6×5 =12600
7vg 1br = 3×1 = 3
The fill in the blanks is missing a ^2 because it is a completing of squares so it's missing something but the answer is:
y = (x+4)^2 +9
Answer:
D. Chi-square test for two-way table
Step-by-step explanation:
To test if there is an association between the percentage of people that successfully stop smoking and the method they used to do so, a random sample of 584 smokers who tried to quit smoking and was orted by the method they used to help themselves to achieve their goal (nicotine-patch or e-cigarettes). After six months, the proportion of subjects that successfully stopped smoking.
In this case, the t-test is not applicable, this statistic is to test the population mean. The variable of the study is the proportion of people that successfully stopped smoking using either method.
To apply Chi-Square tests the condition to be met is that the variable is categorizable and since the data can be organized in a 2x2 table, all expected frequencies should be >5.
The objective of the Goodness-to-fit test is to test if a population follows a certain theoretical model.
In this example, the objective is to compare the proportion of people that successfully quit smoking and the proportion of people that failed by using either method.