Y = t*e^(-t/2)
y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=
y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]
a function can't have one input mapped to multiple outputs. this is the case for where 4 maps to -2 and 2, so remove (4, -2)
Answer: C
Step-by-step explanation: for those who are on Enginuity 2021 there is a chart and the person above me is refering to C
Answer:
8. Louis
9. Rose; Raymond
Step-by-step explanation:
8. An exponent represents the number of times the base appears as a factor in the product.
We use a coefficient to signify repeated addition: 3x means x+x+x.
We use an exponent to signify repeated multiplication. x³ means x·x·x.
So, the expression ...

You can see that the factor 4 appears 7 times in the product, so would be represented in exponential form as ...

Louis has correctly observed this fact. In general, we see that multiplying powers of the same base causes those powers to be added.
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9.
<u>Part A</u>. Rose is correct for the same reason as in problem 8.
5^5 · 5^2 = 5^(5+2) = 5^7
<u>Part B</u>. Raymond is correct. We know that division cancels similar terms from the numerator, so ...

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The rules of exponents we're using here are ...
(a^b)(a^c) = a^(b+c)
(a^b)/(a^c) = a^(b-c)
Answer:
Option A m(3m + 4)(3m - 4)
Step-by-step explanation:
we have

Factor m
Apply difference of squares
we know that
substitute