Answer:
Normal daughters and Hemophiliac son
Explanation:
Females exhibit hemophilia and colorblindness in homozygous genotype only.
The genotype of hemophiliac woman= X^hX^h
The genotype of colorblind man= X^cY
A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son
<h3><u>Answer;</u></h3>
The above statement is <u>False </u>
<h3><u>Explanation;</u></h3>
- Speciation is an evolutionary process in which new species arise. There are three types of speciation, namely; sympatric, parapatric and allopatric speciation.
- <em><u>Sympatric speciation is a pattern in which speciation occurs in the absence of a physical barrier to gene flow; ex. polyploidy arising in flowers.</u></em>
- In an Allopatric speciation on the other hand, a physical barrier arises and separates two populations, ending gene flow between them and allowing reproductive isolating mechanisms to evolve so that later if the two groups come back into contact they will no longer be able to reproduce together, therefore making them different species.
Answer: B) are excited by light that falls in the center of their receptive field.
Explanation:
There are two types of bipolar cells present in the retina which are differentiated on the way the centres of their receptive fields respond to light. The names of bipolar cells are ON-centre and OFF-centre.
If a light fall at the centre of the receptive field of a bipolar cell, it will experience an exciting effect on that cell, resulting in it being depolarized, it is an ON-center cell.
Hence, the correct option is B.
Answer:
The head got bigger and the face got smaller. Hope his helps.
Explanation:
temperature is expelled out from the body in form of sweat
