Can you translate i can help you better
Answer:
Thus, the value of x = -36 when y = 15
Step-by-step explanation:
We know that if y varies directly with x, we can express the relationship such as
y ∝ x
y = kx
k = y/x
where 'k' is called constant of variation.
Given
y = -5
x = 12
Using the equation
k = y/x = -5/12
Thus, the value of k = -5/12
Finding x when y = 15
y = 15
k = -5/12
substituting y = 15 and k = -5/12 in the equation
y = kx
15 = -5/12 (x)
15×12 = -5x
180 = -5x
divding both sides by -5
-5x/-5 = 180/-5
x = -36
Thus, the value of x = -36 when y = 15
Answer:
<em>4x^3(x^2 - 5)</em>
Step-by-step explanation:
First, try to factor a common factor.
GCF of 4 and -20 is 4.
GCF of x^5 and x^3 is x^3.
Factor out 4x^3.
4x^5 - 20x^3 =
= 4x^3(x^2 - 5)
Given, (9x - 4)(9x + 4) = ax² - b
From algebraic identities:
We know, (a + b)(a - b) = a² - b²
Now, 81x² + 36x - 36x - 16 = ax² - b
81x² - 16 = axis² - b
So ax² = 81x²
a = 81
-b = -16
b = 16
Solution
Therefore, the value of a is 81.
<h2>MyHeritage</h2>
